Question

A silver block, initially at 58.5°C, is submerged into 100.0 of water at 24.8°C in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 26.2 °C. What is the mass of the silver block?

Answer 1

Answer:

77.6 g are the mass of silver

Explanation:

This is a calorimetry problem, All the heat released by the silver was gained by the water, so the T° has increased.

Q = m . C . ΔT

mass from silver . 0.056 cal/g°C . (26.2°C - 58.5°C) = 100 g . 1 cal/g°C (26.2°C - 24.8°C)

mass from silver . 0.056 cal/g°C .-32.3°C = 100 g . 1 cal/g°C . 1.4°C

mass from silver . -1.8032 cal/g = 140 cal

mass from silver = 140 cal / 1.8032 g/cal

mass from silver = 77.6 g