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Yuri [45]
3 years ago
13

Triangle DEF is circumscribed about circle R. Points S, T and U are points of tangency where SD = 4 m and UF = 7 m. What is the

measure of DF
Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
First of all, we need to establish some known things. Let us call the radius r and the center of the circle R. Consider RD and then consider the 2 triangles DUR and DSR. We have that they have both a 90 degree angle (due to the tangency condition), they have DR common and also SR is equal to UR since both are equal to r. Hence, we have that the triangles are equal, thus, we have that DS=DU. Since DF=DU+UF, we have that DF=11
Mama L [17]3 years ago
4 0
The measure off DF is 11.

In a circle inscribed within a triangle, the distance from each vertex of the triangle to the two nearest touchpoints (points of tangency on the circle) are equal.  Since SD=4, DT=4 as well.  Since UF=7, then FT=7.  

DF=DT+TF=4+7=11.
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Find all real numbers on the interval [0.2 t) that satisfy the equation. Use radian measure.
sergejj [24]

Answer:

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Step-by-step explanation:

The equation can be put into standard form by adding 1:

  2cos²(x) +3cos(x) +1 = 0

  (2cos(x) +1)(cos(x) +1) = 0

Values of cos(x) that make this true* are ...

  cos(x) = -1/2 . . . . . . . . . true for x=2π/3, x=4π/3

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A graphing calculator can be helpful here, too.

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* from your knowledge of the short table of trig functions and their signs in different quadrants

3 0
3 years ago
What is angle A + angle B<br><br> 34°<br> 56°<br> 90°<br> 180°
STALIN [3.7K]

Answer:

a + b = 90°

Step-by-step explanation:

It’s obvious that this is a right angle then

a + b = 90°

6 0
3 years ago
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Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the
tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

f(x)=4x^{2} -1

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

so

The axis of symmetry is x=0

Part 2) we have

g(x)=x^{2}-8x+5

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

g(x)-5=x^{2}-8x

g(x)-5+16=x^{2}-8x+16

g(x)+11=x^{2}-8x+16

g(x)+11=(x-4)^{2}

g(x)=(x-4)^{2}-11

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

so

The axis of symmetry is x=4

Part 3) we have

h(x)=-3x^{2}-12x+1

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The vertex is a maximum

Convert the equation into vertex form

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h(x)=-3(x+2)^{2}+13

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

so

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

so

h(x),f(x),g(x)

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lara31 [8.8K]

Answer:

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Step-by-step explanation:

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4 years ago
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