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Yuri [45]
3 years ago
13

Triangle DEF is circumscribed about circle R. Points S, T and U are points of tangency where SD = 4 m and UF = 7 m. What is the

measure of DF
Mathematics
2 answers:
bogdanovich [222]3 years ago
7 0
First of all, we need to establish some known things. Let us call the radius r and the center of the circle R. Consider RD and then consider the 2 triangles DUR and DSR. We have that they have both a 90 degree angle (due to the tangency condition), they have DR common and also SR is equal to UR since both are equal to r. Hence, we have that the triangles are equal, thus, we have that DS=DU. Since DF=DU+UF, we have that DF=11
Mama L [17]3 years ago
4 0
The measure off DF is 11.

In a circle inscribed within a triangle, the distance from each vertex of the triangle to the two nearest touchpoints (points of tangency on the circle) are equal.  Since SD=4, DT=4 as well.  Since UF=7, then FT=7.  

DF=DT+TF=4+7=11.
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Allushta [10]

Part a) Use a system of inequalities to model the scenario

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Part c) Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

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using a graph tool

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If the point is a solution, it must satisfy both inequalities.

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5 0
3 years ago
Read 2 more answers
Help!!!<br><br> By rounding each number to 1sf. Estimate the answer to 7.238 × 125.5413
Molodets [167]

Answer:

909

Step-by-step explanation:

I'm not sure if I'm right plz tell me if I'm wrong

6 0
3 years ago
Find the percent of decrease from 280 to 210. Round to the nearest tenth of a percent, if necessary.
Vlada [557]
To find the decreased percentage,here's what we can do:
\frac{originl \: value - new \: value}{originl \: value}  \times 100\%

In this case,the eqaution would be:
\frac{280 - 210}{280}  \times 100\% \\  =  \frac{70}{280}  \times 100\% \\  =  \frac{1}{4}  \times 100\% \\  = 25\%
Hope it helps!
5 0
3 years ago
Find the number of real zeros of
Amiraneli [1.4K]

Answer:

B

Step-by-step explanation:

Using the determinant to determine the type of zeros

Given

f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct zeros

• If b² - 4ac = 0 then 2 real and equal zeros

• If b² - 4ac < 0 then 2 complex zeros

Given

f(x) = (x - 1)² + 1 ← expand factor and simplify

     = x² - 2x + 1 + 1

    = x² - 2x + 2 ← in standard form

with a = 1, b = - 2, c = 2, then

b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4

Since b² - 4ac < 0 then the zeros are complex

Thus P(x) has no real zeros

6 0
3 years ago
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My name is Ann [436]
Is there a picture of the question?
8 0
2 years ago
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