Answer:
March 1
Dr Notes Receivable $10,900
Cr Service Revenue $10,900
September 1
Dr Cash $11,390
Cr Notes Receivable $ 10,900
Cr Interest Revenue $490
Explanation:
March 1
Dr Notes Receivable $10,900
Cr Service Revenue $10,900
(Provide legal services and accept note)
September 1
Dr Cash $11,390
Cr Notes Receivable $ 10,900
Cr Interest Revenue $490
(Receive cash on note receivable and interest)
(Interest revenue = $10,900 x 9% x 6/12) =490.5
The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.
<h3>What is a Compound interest loan?</h3>
Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.
![\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\= [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CR%5C%5C%5C%5CP%20%3D%20%5C%24%5C%2C17%2C550%5C%5Cr%5C%2C%3D%205.32%5C%25%5C%5CTime%5C%2C%3D%20n%3D%207%5C%2Cyears%5C%5CAmount%5C%2Cpaid%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%3D%5B%2017%2C550%20%281%2B%5Cdfrac%7B5.32%7D%7B100%5Ctimes12%7D%29%5E%7B7%5Ctimes12%7D%20%5D%5C%5C%3D%20%5B%2017%2C550%20%28%5Cdfrac%7B12.0532%7D%7B12%7D%29%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%20%5B%2017%2C550%20%281.00443%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%5C%24%2025%2C440.48%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%20%5Crm%5C%2C%5Cdfrac%7B25%2C440.48%7D%7B84%7D%5C%5C%5C%5C%3D%20%5C%24%5C%2C%20%24302.86%5C%5C%5C%5C)
![\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CS%20%3D%5C%5C%5C%5CP%3D%5C%2C%5C%24%2015%2C925%5C%5Cr%5C%2C%3D%206.07%5C%25%5C%5CT%3Dn%3D%209%5C%2Cyears%5C%5C%5C%5CAmount%5C%2Cpaid%5C%2C%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B9%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B108%7D%20%5D%5C%5C%5C%5C%3D%5B15%2C925%281.7247.84%29%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5C%2427%2C467.19%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%5Cdfrac%7B%5Crm%5C%2C%5C%24%5C%2C27%2C469.19%7D%7B108%7D%5C%5C%5C%5C%3D%20%5C%24%20254.326%5C%5C%5C%5C)
The difference between the monthly payment of R and S is equal to $48.53.
Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53
To learn more about Compound interest, refer to the link:
brainly.com/question/14331235
Answer:
the transaction is complete and the goods or services are delivered.
Explanation:
According to generally accepted accounting principles (GAAP), the revenue should be recognized when the goods or services are delivered and the transaction is completed in all respects.
The revenue recognition principle applies when the revenue is realized or earned whether cash is received or not plus it also follows the accrual basis of accounting. Here, realizable means that customer received the product but the payment is made at the later date
A natural monopoly, such as a local electricity provider, is the result of long run average total costs declining continuously as output increases. The correct option among all the options that are given in the question is option "3". The initial cost of power generation and power distribution cost is high. Once the generation starts and the number of consumer increases, the average cost starts declining.
Answer:
Explanation:
Annual demand (D) = 20000 units
Number of days per year = 250
Demand rate(d) = D/number of days per year = 20000/250 = 80 units
Production rate(p) = 655 units
Set up cost(S) = $1800
Holding cost (H) = $1.50
A) Optimum run size(Q) = sqrt of {2DS / H [1-(d/p)]}
= sqrt of {(2x20000x1800) /1.50[1-(80/655)]}
= Sqrt of [7200000/1.50(1-0.1221) ]
= sqrt of [72000000/(1.50 x 0.8779)]
= sqrt of (7200000/1.31685)
= Sqrt of 5467593.1199
= 2338 units
b) Maximum inventory ( I - max) = (Q/p) (p-d) = (2338/655)(655-80) = 3.5695 x 575 = 2052.46 or rounded off to 2052 units
Average inventory = I-max/2 = 2052/2 = 1026 units
C) Number of production setups per year = D/Q = 20000/2338 = 8.55 or rounded up to 6
d) optimal length of production run = optimal run size /production rate = 2338/655 = 3.56 or rounded up to 4 days
