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4 years ago

Plz help me - 5/8 as a decimal?

Mathematics

1 answer:

marin [14]4 years ago

4 0

Answer:

-0.625

Step-by-step explanation:

Given that a fraction negative in value with numerator -5 and denominator 8.

We have to convert this into decimals. For that we add as many zeroes after decimal point after 5 and divide with 8. The quotient what we get is value of the fraction.

To find in decimals, let us divide 5 by adding zeroes to the right

8)5.00000{0.625

4.8

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Hence in decimal form the fraction -5/8 = -0.625

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please answer soon Which expression is equivalent to − 7 x + 6 ( x − 8 2 ) − 2 ( x + 3 ) + 10 ? A. − 3 x + 40 B. − 15 x − 20 C.

Artyom0805 [142]

Multiply the parenthesis by 6:

-7x+6x-492-2(x+3)+10

Multiply the parenthesis by -2:

-7x+6x-492-2x-6+10

Calculate the sum of similar terms:

-3x-492-6+10

Calculate the sum or difference:

-3x-488

6 0

3 years ago

Adding fractions 1/6+2/3=

mars1129 [50]

Answer:

$\frac{5}{6}$

$\frac{1}{6} + \frac{2}{3}$ is equivalent to $\frac{1}{6} + \frac{4}{6}$ .

This is because $\frac{2}{3}=\frac{4}{6}$

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

8 0

3 years ago

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V125BC [204]

Answer:

Dog years will not print an output is the answer

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone help please. I’ll give brainleist.

Jobisdone [24]

I believe the answer is d but tell me if I’m wrong

5 0

3 years ago

A.Find a formula for

Vlada [557]

a. Notice that

1/(1*2) = 1/2 = 1 - 1/2

1/(2*3) = 1/6 = 1/2 - 1/3

1/(3*4) = 1/12 = 1/3 - 1/4

and so on, which suggests the n-th term of the sum can be written as

$\dfrac1{n(n+1)}=\dfrac1n-\dfrac1{n+1}$

Then the sum itself is telescoping:

$\dfrac1{1\cdot2}+\dfrac1{2\cdot3}+\dfrac1{3\cdot4}+\cdots+\dfrac1{n(n+1)}$

$=\left(1-\dfrac12\right)+\left(\dfrac12-\dfrac13\right)+\left(\dfrac13-\dfrac14\right)+\cdots+\left(\dfrac1n-\dfrac1{n+1}\right)$

$=1-\dfrac1{n+1}$

b. The proof is trivial:

$\dfrac1n-\dfrac1{n+1}=\dfrac{n+1}{n(n+1)}-\dfrac n{n(n+1)}=\dfrac{n+1-n}{n(n+1)}=\dfrac n{n+1}$

so the formula found in (a) is correct.

5 0

3 years ago