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3 years ago

Plz help me - 5/8 as a decimal?

Mathematics

1 answer:

marin [14]3 years ago

4 0

Answer:

-0.625

Step-by-step explanation:

Given that a fraction negative in value with numerator -5 and denominator 8.

We have to convert this into decimals. For that we add as many zeroes after decimal point after 5 and divide with 8. The quotient what we get is value of the fraction.

To find in decimals, let us divide 5 by adding zeroes to the right

8)5.00000{0.625

4.8

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Hence in decimal form the fraction -5/8 = -0.625

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The marks scored by a group of students in English examination are as follows: 30,32, 33, 31, 32, 33, 34, 35, 33, 34 . Find the

Alecsey [184]

Answer:

Answer is 32

Step-by-step explanation:

Mode = no of stu +1/2

Mode =12+1/2

Mode =13/28=6.5

Mode =6th mark +7th mark /2

Mode=32+32/2

Mode=64/2

Mode=32

Hope it helps

Peace

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2 years ago

Select all that apply

katovenus [111]

The range is Y>2. :)

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2 years ago

X+20≥-7 i need help pls lollllllllllllllllllllllllll

Zina [86]

Answer:

Step-by-step explanation:

x is greater or equal to 13

7 0

2 years ago

Graph the solution set

antiseptic1488 [7]

Answer:

Graph by first drawing a horizontal line at 3 on the y axis. Anything below this line falls into the y is less than or equal to 3 range. Draw a vertical line at negative 2 on the x axis. This represents x > -2. The next one is a slanted line, so it'll be trickier to graph. If using a graph of 10 - 10, graph from (-8, -10) to (10, 8). If using a graph of 20 - 20, graph from (-18, -20) to (20, 18). As seen in the graph, anything to the upper left of this line is included.

The true inclusion is where all the ranges intersect. Be sure to color this the darkest or with a special pattern.

5 0

3 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

7 0

3 years ago