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3 years ago

Do I have to find a common denominator

Mathematics

2 answers:

Katen [24]3 years ago

6 0

Yea only for fractions man

antoniya [11.8K]3 years ago

5 0

When it comes to fractions yes you do. But to make it easier just multiply the denominators and that should give u a common denominator, they don't always have to be least common.

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the length of a rectangle is 9 inches more than the width. the perimeter is 54 inches. Find the length and width of the rectangl

Keith_Richards [23]

W is width W+9 is length W+W+9=54 2w=45 45/2 W=22.5 Width is 22.5 length is 31.5

7 0

3 years ago

Please help me, you will get 20 points:)

ASHA 777 [7]

Dont listen to the person above, they put the same link everhwher

4 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Find the inequality represented by the graph

Nuetrik [128]

Answer:

y>=1*x+2

Step-by-step explanation:

y>=k*x+n

we know that 2=k+n and 0=-2k+n

so 4=2k+n and 0=-2k+n

now 4=2n so n=2

now k=1

so y>=1*x+2

7 0

3 years ago

Read 2 more answers

A large pizza costs $8.95, plus $0.65 for each additional topping. Ron paid $10.90 for a large pizza. How many additional toppin

svp [43]

X represents # of toppings

8.95+0.65x=10.90
0.65x=1.95
x=3

He got 3 additional toppings onto his large pizza.

5 0

3 years ago