Answer : The length of the wire is, 8533 cm
Step-by-step explanation :
As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.
Volume of iron sphere = Volume of cylindrical wire
The formula will be:
![\frac{4}{3}\pi r_1^3=\pi r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r_1%5E3%3D%5Cpi%20r_2%5E2h)
where,
= radius of sphere = ![\frac{Diamtere}{2}=\frac{8cm}{2}=4cm](https://tex.z-dn.net/?f=%5Cfrac%7BDiamtere%7D%7B2%7D%3D%5Cfrac%7B8cm%7D%7B2%7D%3D4cm)
= radius of cylindrical wire = ![\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm](https://tex.z-dn.net/?f=%5Cfrac%7BDiamtere%7D%7B2%7D%3D%5Cfrac%7B2mm%7D%7B2%7D%3D1mm%3D0.1cm)
h = height of cylindrical wire or length of wire
Now put all the given values in the above formula, we get:
![\frac{4}{3}\pi r_1^3=\pi r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r_1%5E3%3D%5Cpi%20r_2%5E2h)
![\frac{4}{3}\times r_1^3=r_2^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20r_1%5E3%3Dr_2%5E2h)
![\frac{4}{3}\times (4)^3=(0.1)^2h](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20%284%29%5E3%3D%280.1%29%5E2h)
![h=8533.33cm\approx 8533cm](https://tex.z-dn.net/?f=h%3D8533.33cm%5Capprox%208533cm)
Therefore, the length of the wire is, 8533 cm
Collinear points lie on the same line. So, you must look for other points that lie on the line that connects A and N. If you start from A and continue along that line, you can see that, after N, you will meet points M and F.
So, those points are collinear with A and N.
0.75x + 0.5y = 25.....and she doesn't want any licorice....so x = 0
0.75(0) + 0.5y = 25
0.5y = 25
y = 25/0.5
y = 50....she can get 50 cherry candies
Answer:
All of the above
Step-by-step explanation:
Any rigid transformation is a similarity transformation. So, too, is (uniform) dilation.