Answer:
segment bisector
Step-by-step explanation:
Too cut in half, think bisect.
So we are talking about a segment, so segment bisector
Starting from the fundamental trigonometric equation, we have
Since , we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have
Plugging the numbers, we have
Now, just recall that
to deduce
Using the midpoint formula, the coordinates of endpoint H are (4, -6).
<h3>The Midpoint Formula</h3>
The midpoint formula is given as:
<em>Where</em>,
= coordinates of the midpoint
= coordinates of the first point
= coordinates of the second point
Given the following:
= M( 6,-4)
= G(8,-2)
= H(?, ?)
Plug in the values into the midpoint formula
Solve for the x-coordinate and y-coordinate separately
Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).
Learn more about midpoint formula on:
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We will conclude that:
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
<h3>
Comparing the domains and ranges.</h3>
Let's study the two functions.
The exponential function is given by:
f(x) = A*e^x
You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:
y > 0.
For the logarithmic function we have:
g(x) = A*ln(x).
As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:
So the range of the logarithmic function is the set of all real numbers.
<h3>So what we can conclude?</h3>
- The domain of the exponential function is equal to the range of the logarithmic function.
- The domain of the logarithmic function is equal to the range of the exponential function.
If you want to learn more about domains and ranges, you can read:
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