Question

The math club sells candy bars and drinks during football games.60 candy bars and 110 drinks will sell for $265120 candy bars and 90 drinks will sell for $270How much does each candy bars sell for?*Can yall work the whole problem out so I can see it Thanks*

Answer 1

Let candy bars =xLet drinks =y Set up the two equations. 60x + 110y = 265120x + 90y = 270 Solve through elimination.  Multiple the first equation by 2 and subtract the second equation from the first. When we multiply the first equation by two, we get: 2(60x +110y = 265) = 120x + 220y = 530 Then, when we subtract the second from the first we get: (120x + 220y = 530) - (120x +90y = 270) The result is 130y = 260 So, y=2 Then, we plug that back in to the original equation to find x. 60x + 220 = 265 Subtract 220 from both sides. 60x = 45 x = .75 So, drinks cost 2 dollars and candy bars cost 75 cents.







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