Help i'm taking a math quiz

ᗩ ᗰᗩᑕᕼIᑎE ᑕᗩᑎ ᑭᗩᑕKᗩGE 5950 ᗷO᙭Eᔕ Oᖴ ᑕEᖇEᗩᒪ Iᑎ 7 ᕼOᑌᖇᔕ . ᕼOᗯ ᗰᗩᑎY ᗷO᙭Eᔕ Iᔕ TᕼE ᗰᗩᑕᕼIᑎE ᑭᗩᑕKIᑎG ᑭEᖇ ᕼOᑌᖇ

aliya0001 [1]

850. I am not really sure because i divided

7 0

4 years ago

The walls of a square room need painting. each of the four walls is 12ft wide by 8.5 feet tall. one gallon of paint covers 75fts

miv72 [106K]

The surface to be paint is 4 * 12*8.5= 408 ft squared

1 gallon.......75 ftsquared
x gallon.......408 ft squared
------------------------------------
x= 408/75= 5,44 gallons

7 0

3 years ago

A company made 4 million in the second quarter this is 1/3 more then it made in the first quarter and 4/5 of what it made in the

Ratling [72]

In this problem, you have to find the total profit the company made in the three quarters which makes up 3/4 of the whole. In the second quarter, the profit is 4 million. Let x be the profit in the first quarter. Following the description,

4 = (1+1/3)x
x = 3 million

Thus, the second quarter made 5.33 million profit.

For the third quarter, let's assign it to the y variable. Following the description,

4 = (4/5)(y)
y = 5 million

Thus, the total profit is 4 + 3 + 5 = 12 million

7 0

3 years ago

The coordinates of A, B, and C in the diagram are A(p,4), B(6,1), and C(9,q). Which equation correctly relates p and q?

siniylev [52]

Answer:

$q+p=7$

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

In this problem line AB and line BC are perpendicular

so

$m_A_B*m_B_C=-1$

step 1

Find the slope AB

we have

A(p,4), B(6,1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{1-4}{6-p}$

$m_A_B=-\frac{3}{6-p}$

step 2

Find the slope BC

we have

B(6,1), and C(9,q)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{q-1}{9-6}$

$m_B_C=\frac{q-1}{3}$

step 3

Find the equation that relates p and q

we know that

$m_A_B*m_B_C=-1$

we have

$m_A_B=-\frac{3}{6-p}$

$m_B_C=\frac{q-1}{3}$

substitute

$(-\frac{3}{6-p})(\frac{q-1}{3})=-1$

$(\frac{q-1}{6-p})=1$

$q-1=6-p\\q+p=7$

3 0

3 years ago

A group of entomologists has determined that the population of ladybugs at a local park can be modeled by the equation y = − 1.4

Oksanka [162]

<h3>Answer:</h3>

A) 177.568 thousand.

B) 125.836 thousand.

<h3>Step-by-step explanation:</h3>

In this question, it is asking you to use the equation to find the population of ladybugs in a certain year.

Equation we're going to use:

$y = -1.437 x + 197.686$

We know that the "x" variable represents the number of years since 2010, so that means our starting year is 2010.

Lets solve the question.

Question A:

We need to find the ladybug population is 2024.

2024 is 14 years after 2010, so our "x" variable will be replaced with 14.

Your equation should look like this:

$y = -1.437 (14) + 197.686$

Now, we solve.

$y = -1.437 (14) + 197.686\\\\\text{Multiply -1.437 and 14}\\\\y=-20.118+197.686\\\\\text{Add}\\\\y=177.568$

You should get 177.568

This means that the population of ladybugs in 2024 is 177.568 thousand.

Question B:

We need to find the ladybug population is 2060.

2060 is 50 years after 2010, so the "x" variable would be replaced with 50.

Your equation should look like this:

$y = -1.437 (50) + 197.686$

Now, we solve.

$y = -1.437 (50) + 197.686\\\\\text{Multiply -1.437 and 50}\\\\y=-71.85+197.686\\\\\text{Add}\\\\y=125.836$

This means that the population of ladybugs in 2060 would be 125.836 thousand.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

7 0

4 years ago