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Elan Coil [88]
3 years ago
15

Help i'm taking a math quiz

Mathematics
1 answer:
Agata [3.3K]3 years ago
3 0

Answer: the second one good luck on the test

Step-by-step explanation:

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In a sample of nequals16 lichen​ specimens, the researchers found the mean and standard deviation of the amount of the radioacti
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Answer:

(a) The confidence level desired by the researchers is 95%.

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Step-by-step explanation:

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\bar x=0.009\\s=0.003

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The (1 - <em>α</em>)% confidence interval for population mean (μ) is:

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(a)

The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.

In this case the researches wants to estimate the mean using the 95% confidence interval.

Thus, the confidence level desired by the researchers is 95%.

(b)

In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.

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In this case the margin of error is 0.001 microcurie per millilitre.

(c)

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the sample size value as follows:

MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\times s}{MOE}]^{2}

          =[\frac{1.96\times 0.003}{0.001}]^{2}

          =34.5744\\\approx36

Thus, the sample size necessary to obtain the desired estimate is 36.

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3 years ago
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