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erma4kov [3.2K]
3 years ago
8

A 1200-kilogram space vehicle travels at 4.8 meters per second along the level surface of Mars. If the magnitude of the gravitat

ional field strength on the surface of Mars is 3.7 newtons per kilogram, the magnitude of the normal force acting on the vehicle is
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
<span>The normal force acting on the vehicle is 4440 N. Normal force is the force perpendicular to the ground. The important given values are the mass of the space vehicle (1200 kg) and the gravitational field strength (3.7 N/kg). To get a value of Force in Newtons, we just multiply the two numbers together: force = field strength * mass = 3.7 N/kg * 1200 kg = 4440 N.</span>
Gnom [1K]3 years ago
7 0

The correct answer to the question is : 4,400 N.

EXPLANATION:

The mass of the space vehicle m = 1200 Kg.

The speed of the space vehicle v = 4.8 m/s.

The gravitational field strength E = 3.7 N/Kg.

We are asked to calculate the normal force on the space vehicle.

The gravitational force that acts on the space vehicle is calculated as -

                                Force F = E × m

                                              = 3.7 N/ Kg × 1200 Kg.

                                               = 4.440 N.

The normal reaction on the space craft is equal to the force of gravity on Mars.

Hence, the normal reaction on the space vehicle is 4,440 N.


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Answer:

The magnitude of the new electric field is <u>35820 N/C</u>.

Explanation:

Given:

Original magnitude of electric field (E₀) = 2388 N/C

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Original separation between the plates = 'd' (Assume)

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New distance is 1/5 the original distance. So, d_n=\dfrac{d}{5}

Now, electric field between the parallel plates originally is given as:

E_0=\frac{V}{d}=2388\ N/C

Let us find the new electric field based on the above formula.

E_n=\frac{V_n}{d_n}\\\\E_n=\frac{3V}{\frac{d}{5}}\\\\E_n=15(\frac{V}{d})

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Observations:

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Finally, The Cosmos Background Explorer (COBE) which launched a satellite in the year 1989 found that there were slight fluctuations in the radiation spectrum. The temperature varies very slightly from one place to another by a few parts in 100,000 i.e (10^-5). The excerpts above clarify the reason for the answer to statement four(4) being listed as an Observation.

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