Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plate
1 answer:
Answer:
The magnitude of the new electric field is <u>35820 N/C</u>.
Explanation:
Given:
Original magnitude of electric field (E₀) = 2388 N/C
Original voltage = 'V' (Assume)
Original separation between the plates = 'd' (Assume)
Now, new voltage is three times original voltage. So,
New distance is 1/5 the original distance. So,
Now, electric field between the parallel plates originally is given as:
Let us find the new electric field based on the above formula.
Now, . So,
Therefore, the magnitude of the new electric field is 35820 N/C.
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Answer:
No, not necessarily
Explanation:
If an object is moving with an acceleration that causes its speed to be reduced, there will be a moment in which it reaches v = 0, but this doesn't necessarily mean that the acceleration isn't acting anymore. If the object continues its movement with the same acceleration, it's velocity will become negative.
An example of an object that has zero velocity but non-zero acceleration:
If you throw an object in the air with a certain velocity, it will move vertically, reducing its velocity in a 9,8 rate (which is the acceleration caused by gravity). At a certain point, the object will reach its maximum height, and will start to fall. In the exact moment that it reaches the maximum height, before it starts falling, its velocity is zero, but gravity is still acting on the object (this is the reason why it starts falling instead of just being stopped at that point). Therefore, at that point, the object has zero velocity but an acceleration of 9,8
.
Answer:
Explanation:
For this problem, we need to apply the formulas of constant accelerated motion.
To obtain the boat displacement we need to calculate the displacement because of the river flow and the displacement done because of the boat motor.
for the river:
for the boat:
So the final displacement is given by: