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3 years ago

How’d the turtle cross the road

Physics

2 answers:

Mumz [18]3 years ago

7 0

Answer:

He crawled.

Explanation: He crawled with the strength he gained from a leaf.

cestrela7 [59]3 years ago

4 0

He did it by doing it.....

You might be interested in

Complete the sentence with the word "element" or "compound." O is a(n) and H202 is a(n)

Sauron [17]

Answer:

O is an element and H2O2 is a compound.

Explanation:

O is a single element while H2O2 has 2 elements, which makes it a compound.

5 0

3 years ago

Calculate the pressure exerted by 11.1 moles of neon gas in a volume of 5.45 L at 25°C using (a) the ideal gas equation and (b)

Ilia_Sergeevich [38]

Answer:

49.82414 atm

50.74675 atm

Explanation:

P = Pressure

V = Volume = 5.45 L

R = Gas constant = 0.08205 L atm/mol K

T = Temperature = 25°C

a = 0.211 atm L²/mol²

b = 0.0171 atm L²/mol²

From ideal gas law we have

$PV=nRT\\\Rightarrow P=\dfrac{nRT}{V}\\\Rightarrow P=\dfrac{11.1\times 0.08205(273.15+25)}{5.45}\\\Rightarrow P=49.82414\ atm$

The pressure is 49.82414 atm

From Van der Waals equation we have

$\left(P+\frac{an^2}{V^2}\right)\left(v-nb\right)=nRT\\\Rightarrow P=\dfrac{nRT}{V-nb}-\dfrac{an^2}{V^2}\\\Rightarrow P=\dfrac{11.1\times 0.08205\times (273.15+25)}{5.45-(11.1\times 0.0171)}-\dfrac{0.211\times 11.1^2}{5.45^2}\\\Rightarrow P=50.74675\ atm$

The pressure is 50.74675 atm

3 0

3 years ago

What is umax,c, the value of the maximum energy stored in the capacitor during one cycle?

TiliK225 [7]

1) 0.266 H

2) 0.040 J

3) $0.308\Omega$

Explanation:

The diagram of the circuit is missing: find it in attachment.

1) What is L, the value of the inductance of the circuit?

For an RLC circuit, the resonant angular frequency is given by:

$\omega=\frac{1}{\sqrt{LC}}$

where

L is the inductance of the circuit

C is the capacitance of the circuit

In this problem, we have:

$\omega=164 rad/s$ is the angular frequency of the generator, at which the circuit is in resonance

$C=140 \mu F = 140\cdot 10^{-6}F$ is the capacitance

Therefore, solving for L, we find the inductance of the circuit:

$L=\frac{1}{\omega^2 C}=\frac{1}{(164)^2(140\cdot 10^{-6})}=0.266 H$

2) What is umax,c, the value of the maximum energy stored in the capacitor during one cycle

The maximum energy stored in a capacitor is given by the equation

$U=\frac{1}{2}CV^2$

where

C is the capacitance of the capacitor

V is the maximum potential difference across the capacitor

Here we have:

$C=140 \mu F = 140\cdot 10^{-6}F$ is the capacitance

$V=24 V$ is the maximum voltage across the capacitor, which is the emf of the generator

Substituting, we find:

$U=\frac{1}{2}(140\cdot 10^{-6})(24)^2=0.040 J$

3) What is R, the value of the resistance of the circuit?

Here we want to find the resistance of the circuit.

The resistance of the circuit can be found by using Ohm's Law:

$V=RI$

where

V is the maximum voltage

R is the resistance

I is the maximum current

Here we have:

V = 24 V is the maximum voltage provided by the generator

I = 0.78 A is the maximum current in the circuit

Solving for R, we find the resistance:

$R=\frac{V}{I}=\frac{0.24}{0.78}=0.308\Omega$

6 0

4 years ago

Calculate the kinetic energy of a 5.2 kg object moving at 2.4 m/s.

Lilit [14]

Answer:

Kinetic energy, K = 14.97 J

Explanation:

We have,

Mass of the object, m = 5.2 kg

Velocity of the object, v = 2.4 m/s

It is required to find the kinetic energy of the object. As it is moving with some velocity, it will have kinetic energy. It is given by :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5.2\times (2.4)^2\\\\K=14.97\ J$

So, the kinetic energy of the object is 14.97 J.

7 0

3 years ago

A semicircular plate with radius 6 m is submerged vertically in water so that the top is 2 m above the surface. Express the hydr

dalvyx [7]

Answer: 313920

Explanation:First, we’re going to assume that the top of the circular plate surface is 2 meters under the water. Next, we will set up the axis system so that the origin of the axis system is at the center of the plate.

Finally, we will again split up the plate into n horizontal strips each of width Δy and we’ll choose a point y∗ from each strip. Attached to this is a sketch of the set up.

The water’s surface is shown at the top of the sketch. Below the water’s surface is the circular plate and a standard xy-axis system is superimposed on the circle with the center of the circle at the origin of the axis system. It is shown that the distance from the water’s surface and the top of the plate is 6 meters and the distance from the water’s surface to the x-axis (and hence the center of the plate) is 8 meters.

The depth below the water surface of each strip is,

di = 8 − yi

and that in turn gives us the pressure on the strip,

Pi =ρgdi = 9810 (8−yi)

The area of each strip is,

Ai = 2√4− (yi) 2Δy

The hydrostatic force on each strip is,

Fi = Pi Ai=9810 (8−yi) (2) √4−(yi)² Δy

The total force on the plate is found on the attached image.

5 0

3 years ago