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Naddika [18.5K]
2 years ago
15

How’d the turtle cross the road

Physics
2 answers:
Mumz [18]2 years ago
7 0

Answer:

He crawled.

Explanation: He crawled with the strength he gained from a leaf.

cestrela7 [59]2 years ago
4 0

He did it by doing it.....

You might be interested in
Sometimes students are taught that "air expands as it is heated". And sometimes they are taught that "as air expands it cools".
hram777 [196]

Answer:

Both are true under specific circumstances. And are related to Boyle's law. volume and pressure in a gas are inversely proportional.

Explanation:

There is a tendency to entropy in our reality, that is, in particular true and visible with gases, they tend to occupy the whole space where they are confined, when we heat a volume of gas, then the movement of the particles and in consequence the pressure of the gas increases and to compensate this the volume tends to be increased too, according to Boyle's law. And the opposite happens when the volume is increased, then the pressure is  relieved and since the particles are further one from each other, then the temperature is lower, and therefore it cools down.

7 0
3 years ago
A 1400-kg car is moving at a speed of 25m/s. how much kinetic energy does the car have?
Luba_88 [7]

Answer:

437.5Kjoules

Explanation:

K.E=half multiply by mass multiply by square of velocity

=437.5Kjoules

3 0
2 years ago
if a car travels 30 miles north for one half hour, 50 miles east for one hour, and 30 miles south for 30 minutes, what is the to
egoroff_w [7]
50 miles east. because the 30 miles north then south cancel each other out. 
5 0
3 years ago
Read 2 more answers
Do the two cars ever have the same velocity at one instant of time? If so, between which two frames? Check all that apply. Check
alexgriva [62]

Answer:

Cars have the same velocity at one instant of time between dots 4 and 5.

Explanation:

after looking at the image it is visible that same distance is covered by both cars in the frame between 4 and 5

8 0
3 years ago
Ali is whirling a 2.0 kg bunch of bananas in a circular path having a radius of 0.50 m. The bananas complete 2 revolutions every
skad [1K]

Answer:

1) 2.467 N

2) a) 0.248m

   b) 2.3π rad/sec

Explanation:

Given data:

mass of Banana bunch ( m ) = 2.0 kg

radius of circular path ( R ) = 0.5 m

number of revolutions completed = 2

Time to complete 2 revolutions = 6 seconds

1) Determine the force to keep the motion constant for one complete revolution in every 4 seconds

F = mv^2 / r ----- ( 1 )

where V = 2πR/T

where : R = 0.5 , m = 2, T = 4 seconds

Insert values into equation 1

F = 2 * 4π^2 * 0.5/4^2

 = 2.467 N

2a) Calculate the maximum distance of coin from center

angular velocity ( w ) = v/r

coefficient of static friction  ( μ ) = 0.25

F_{c} = u mg  ---- ( 1 )

mv^2/r = μmg --- ( 2 )        cancelling the mass on both sides eqn 2 becomes

v^2 = μ*g*r

dividing both sides of equation by r^2

w^2 = μ*g/r

hence determine distance ( r ) of coin from center

r = 0.25 * 9.81 / π^2 =  0.248 m

2b ) determine the maximum speed of rotation of the turntable for the coin to move relative to the turntable without slipping

distance coin is placed ( r ) = 4.7 cm = 0.047 m

find speed of rotation ( w )

w^2 =  μ*g/r

w = √ 0.25 * 9.81/ 0.047

   = 7.2236 rad/secs ≈  2.3π rad/sec

       

3 0
2 years ago
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