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Marta_Voda [28]

3 years ago

10

A speck of dust with mass 12 mg and electric charge 10 μC is released from rest in a uniform electric field of magnitude 850 N/C

. Calculate the acceleration of the dust speck, ignoring gravitation. ______ m/s^2

1 answer:

Marta_Voda [28]3 years ago

4 0

Answer:

$a=708.3m/s^2$

Explanation:

The force experimented by a charge <em>q </em>in a uniform electric field <em>E</em><em> </em>is <em>F=qE</em>.

Newton's 2nd Law tells us that the relation between acceleration <em>a</em> a mass <em>m </em>experiments when a force <em>F </em>is applied to it is <em>F=ma</em>.

Combining these equations we have <em>am=qE</em>, and since we want the acceleration of the speck of dust, we substitute our values:

$a=\frac{qE}{m}=\frac{(10\times10^{-6}C)(850N/C)}{12\times10^{-6}Kg}=708.3m/s^2$

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GIVEN

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(b)

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