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3 years ago

Which is an example of the force of attraction between two objects that have mass?

Physics

1 answer:

Mariulka [41]3 years ago

4 0

Answer:

Gravity is an example of the force of attraction between two objects that have mass.

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Explain, using your own words, how noise cancelling headphones work, (physics)

Afina-wow [57]

Answer:

They use noise control, creating a wave that negates outside or ambient sound and replaces it with the desired sound that listeners request.

Explanation:

I hope this helped

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3 years ago

A 500 N force accelerates an object at 20 m s-2. What is its mass?

avanturin [10]

Answer: The mass of the object is 25kg.

The given question deals with Newton's second law of motion and its applications.

Explanation: Given force, F=500N

acceleration, a=20 m/ $s^{2}$

From Newton's 2nd law of motion , we have

F=ma where m=mass of the object

⇒500=m×20

⇒m=500/20=25

∴ Mass of the object is 25 kg .

Reference Link: brainly.com/question/1141170

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2 years ago

How does the suns gravitational attraction impact earths motion

Savatey [412]

The lighter object is in orbit around the heaviest, and the Sun is the heaviest object in the Solar System

5 0

3 years ago

Which of the following statements is true? The square root of the molecular weight of a gas is equal to its rate of diffusion. T

forsale [732]

The diffusion coefficient of the gas is proportional to the average rate of thermal motion of the molecules.

the average velocity is inversely proportional to the square root of the molar mass

so
The gas diffusion rate is inversely proportional to the square root of its molecular weight.

8 0

3 years ago

Read 2 more answers

The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of

natita [175]

Answer:

3.258 m/s

Explanation:

k = Spring constant = 263 N/m (Assumed, as it is not given)

x = Displacement of spring = 0.7 m (Assumed, as it is not given)

$\mu$ = Coefficient of friction = 0.4

Energy stored in spring is given by

$U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J$

As the energy in the system is conserved we have

$\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s$

The speed of the 8 kg block just before collision is 3.258 m/s

7 0

3 years ago