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BartSMP [9]
3 years ago
14

How do you this question (pre-cal)

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

The goal to proving identities is to transform one side into the other. We can only pick one side to transform while the other side stays the same the entire time. The general rule of thumb is to transform the more complicated side (though there may be exceptions to this guideline).

So I'll take the left hand side and try to turn it into \csc^2( B )

One way we can do that is through the following steps:

\frac{\tan(B) + \cot(B)}{\tan(B)} = \csc^2(B)\\\\\frac{\tan(B)}{\tan(B)} + \frac{\cot(B)}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\frac{1}{\tan(B)} = \csc^2(B)\\\\1 + \cot(B)*\cot(B) = \csc^2(B)\\\\1 + \cot^2(B) = \csc^2(B)\\\\1 + \frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)}{\sin^2(B)}+\frac{cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{sin^2(B)+cos^2(B)}{\sin^2(B)} = \csc^2(B)\\\\\frac{1}{\sin^2(B)} = \csc^2(B)\\\\\csc^2(B)=\csc^2(B) \ \ {\Large \checkmark}\\\\

Since we've shown that the left hand side transforms into the right hand side, this verifies the equation is an identity.

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Solve x-5y=-30, 3x+5y=10 show your work
marin [14]

1) x = 5y - 30  

2) x = - 1.6y + 3.3

<em>im assuming these are 2 different questions</em>

<h3>Explanation:</h3><h3>1)</h3>

Start with the equation:

x - 5y= -30

add 5y to both sides:

x = 5y - 30

Your answer is x = 5y - 30  

<h3>2)</h3>

Start with the equation:

3x+5y=10

subtract 5y from both sides:

3x = -5y + 10

divide by 3 to get x singular

x = - 1.6y + 3.3

Your answer is x = - 1.6y + 3.3

Hope this helps :)

6 0
2 years ago
What is 5 + 2/9 + 4 + 11/13 please and thank you I need help
natima [27]

Answer:

10.0683760684

Step-by-step explanation:

3 0
3 years ago
SOLVE THIS PLEASE!<br><br><br> -5x-10=2-(x+4)
Alexxandr [17]
The answer would be X=-2
7 0
3 years ago
Read 2 more answers
What are the ordered pairs of the solutions for this system of equations? f(x)=x2-2x+3; f(x)=-2x+28
Alenkasestr [34]

Answer: (5,18); (-5,38)

Step-by-step explanation:

x^2-2x+3=-2x+28

x^2-25=0

(x-5)(x+5)= 0

-2(5)+28= 18

-2(-5)+28=38

(5,18)(-5,38)

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-10x%2B5-3%28x-5%29" id="TexFormula1" title="x^{2} -10x+5-3(x-5)" alt="x^{2} -10
stellarik [79]

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8 0
2 years ago
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