Step 1 is to find how far apart W and Y are:
-7 - (-31) = 24
Now find 1/8 of that distance: 1/8 • 24 = 3
Now move 3 units from -31 towards -7: -31 + 3 = -28
I´d say "d" is the distance from the eye to the wall.
Now substracting 1.2-1 you´ll get the distance of the wall of the smallest triangle = 0.2 And you do 1.5-0.2= 0.3 that´s the distance of the wall of the other triangle. Then you solve everything with Pitagoras theorem. You have 2 rectangle triangles.
B+alfa=45°
tan^-1(0.2/d)=B
tan^-1(1.3/d)=alfa
THEN:
tan^-1(0.2/d)+tan^-1(1.3/d)=45°
Now you have 3 ecs and 3 variables.
alfa,B and "d"
Answer:
40
Step-by-step explanation:
Its pretty easy i did that on a test and got a 100
Answer:(X^2-11)(2X-5)
Step-by-step explanation:
2x^3-5x^2-22x+55
x^2(2x-5)-11(2x-5)
(X^2-11)(2X-5)
6m+6n=-30
6m-5n=14
11n=-44
n=-4
m=-1
Ordered pair is (-1,-4)
