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gregori [183]
3 years ago
13

How many solutions does 10+5x/15=4 have

Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0

Answer:never give up

Step-by-step explanation:

Yo

NemiM [27]3 years ago
5 0

Answer:

3

Step-by-step explanation:

Standard form

1/3 x +6 = 0

Factorization

1/3 (x + 18) = 0

Solutions

x = -90/5 = 18

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The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
ivolga24 [154]

Answer:

B

Step-by-step explanation:

f(0) - f(-3) = area under f'(x) from x=0 to x=3.

We can find the area under f'(x) in this interval by finding the area of the triangle formed by the line.

A = 1/2 b h

A = 1/2 (3) (3)

A = 4.5

f(0) - f(-3) = 4.5

Since f(0) = 7:

7 - f(-3) = 4.5

f(-3) = 7 - 4.5

f(-3) = 2.5

4 0
3 years ago
What is the solution to this system of equation?<br><br> x=2y-4<br> 7x+5y= -66
mina [271]

Answer:

Step-by-step explanation:

oh gosh

im sorry but idk how to solve that, mabye if i say you are smart you will be motivated?

8 0
3 years ago
Read 2 more answers
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
Please select the best answer from the choices provided
mixas84 [53]

Answer:

B is the best

Step-by-step explanation:

5 0
3 years ago
Write equation in standard form:<br> 1.y=3/4x+5<br><br><br> 2.y+4=1/3(x+6)
Gwar [14]
1. 3x - 4y = 20

2. x - 3y = -6
5 0
3 years ago
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