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3 years ago

Using the Law of sines, in triangle ABC, if measurement of angle B = 105°, b = 23, a = 14, find measurement of angle A

Mathematics

1 answer:

Degger [83]3 years ago

3 0

Check the picture below.

make sure your calculator is in Degree mode.

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Simplify: x^5. X-^5?

WARRIOR [948]

Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

7 0

3 years ago

I can’t find the the square centimeters of this

Temka [501]

Answer: 544?

Step-by-step explanation:

This is the answer if I'm supposed to solve the question in yellow

1/2*16(48+20) = 1/2*16*(68)

1/2*16=8

8*68 = 544

7 0

3 years ago

Math help please FAST

Tasya [4]

Answer:

180

Step-by-step explanation:

Angles in a triangle add up to equal 90 degrees

Equilateral - has all congruent angles and congruent sides

If a triangle has 3 angles and the angles add up to equal 180 then the measure of one angle in an equilateral = 180 / 3 = 60

Bisect means to split into to equal parts

So if you bisect an 80 degree angles you will have two 40 degree angles. ( Because 80/2 = 40 )

3 0

3 years ago

Read 2 more answers

What is the y-intercept of the line graphed below?

oksano4ka [1.4K]

Answer:

the y intercept is five

Step-by-step explanation:

the line crosses the y axis at 5

7 0

3 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

3 years ago