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vlabodo [156]
3 years ago
14

What volume is occupied by 8.7 g of chlorine gas, Cl2, at 23°C and 1.15 atm pressure

Chemistry
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

V = 5.17L

Explanation:

Mass of gas = 8.7g

T = 23°C = (23 + 273.15)K = 296.15K

P = 1.15 atm

V = ?

R = 0.082atm.L / mol.K

From ideal gas equation

PV = nRT

P = pressure of the gas

V = volume of the gas

n = no. Of moles

R = ideal gas constant

T = temperature of the gas

no of moles = mass / molar mass

Molar mass of Chlorine = 35.5g / mol

No. Of moles = 8.7 / 35.5

No. Of moles = 0.245 moles

PV = nRT

V = nRT / P

V = (0.245 * 0.082 * 296.15) / 1.15

V = 5.9496 / 1.15

V = 5.17L

The volume of the gas is 5.17L

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7.49 x 105 mm<br> 34500 inches<br> 0.45 miles<br> 885 yards<br> smallest to largest lengths
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30.962
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answer:

7.49 x 105 mm
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reason:

I converted all the measurements to inches.
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Since the last one was already in inches, all I needed to do was put them in order from least to greatest
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QUESTION 7 Can you use alligation for any type of liquid? ​
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A compound with molecular formula C6H15N exhibits a singlet at d 0.9 (1H), a triplet at d 1.10 (3H), a singlet at d1.15 (9H), an
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Explanation:

 

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In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group

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