Answer:
it holds reactant molecules in a good position for then to react
) adding phosphoric acid, said phosphoric acid reacting with said calcium carbonate to release gaseous carbon dioxide bubbles, and said water providing water of hydration to said plaster of Paris to form gypsum that sets around said carbon dioxide bubbles thereby forming said foamed plaster.
30.962
34500
28512
31860
answer:
7.49 x 105 mm
0.45 miles
885 yards
34500 inches
reason:
I converted all the measurements to inches.
First, I multiplied 7.49x105 to get 786.45mm
Then, I divided it by 25.4 to get about 30.92 inches
Next, I converted 0.45 miles to inches by multiplying it by 63,360 to get 28,512 inches
For the yards, I took 885 and multiplied it by 36 to get 31,860 inches
Since the last one was already in inches, all I needed to do was put them in order from least to greatest
Answer:
Yes you can use alligation for a type of liquid. Explanation: Alligation is an old and practical method of solving arithmetic problems related to mixtures of ingredients.
Answer:
N-ethyl-2-methylpropan-2-amine
Explanation:
In this case, we have to start with the <u>IR info</u>. The signal on 3400 cm^-1 indicates the presence of a <u>hydrogen bonded to the heteroatom</u>. In this case, we have nitrogen in the formula, so we will have the <u>amine group</u>.
On the other hand, we have to analyze the NMR info:
a) We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.
b) We have a triplet => This indicates the presence of <u>CH3 bonded to a CH2</u>.
c) We have a quartet => This indicates the presence of <u>CH2 bonded to a CH3</u>.
From b) and c) we can conclude that we have the <u>ethyl group</u> bonded to a nitrogen.
Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the <u>ter-butyl group</u>.
In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group