1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hichkok12 [17]
3 years ago
7

What two-step process separated the cans into aluminum, steel, and tin?

Chemistry
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

Magnet

Durability and heaviness.(texture)

Explanation:

Magnet can be use to separate Aluminum from mixture of steel and aluminum.

Though aluminum and steel look alike but magnet can be use to separate it.

If the can attract the magnet or magnet stick to the can, it is a steel can. Aluminum does not stick to magnet.

A mixture of Aluminum and tin can also be separated by magnet.

Tin attract magnet but tin is more durable, heavy and does not corrode easily.

When u touch the three cans, tin is heavy and durable.

You might be interested in
1. a Use the valence electron molecular orbital diagram for F2 to propose ground state F2ions that satisfy the following conditi
ikadub [295]
If 2.34 moles of Mg react with 3.56 moles of l2 and 1.76 moles of Mgl2 form, what is the percent yield?
3 0
2 years ago
Onsider the following reaction at equilibrium:
11111nata11111 [884]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

C(s)+H_2O(l)\leftrightharpoons CO(g)+H_2(g)

A. C is added to the reaction mixture.

If the concentration of reactant specie is increased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in concentration of reactant specie occurs. So, on increasing C ,equilibrium will shift in right direction.

B. H_2O is condensed and removed from the reaction mixture.

If the concentration of reactant specie is decreased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in concentration of reactant specie occurs. So, on removing water vapor ,the equilibrium will shift in left direction.

C. CO is added to the reaction mixture.

If the concentration of product specie is increased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in concentration of product specie occurs. So, on increasing CO, the equilibrium will shift in left direction.

D. H_2 is removed from the reaction mixture.

If the concentration of product specie is decreased , according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in concentration of product specie occurs. So, on removing hydrogen , the equilibrium will shift in right direction.

5 0
3 years ago
What is the formula for titanium (I) dichromate?
MaRussiya [10]
The answer is TI(Cr207)2
8 0
3 years ago
Compare your predicted ranking of the objects’ volumes with their final ranking based on their measurements. What are the advant
Schach [20]

Answer:

Since its data sample can be quantified using fixed numerical parameters, quantitative observation yields more accurate results than qualitative observation and it is suitable for statistical investigations.

Explanation:

8 0
3 years ago
At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c
ivolga24 [154]

<u>Answer:</u> The equilibrium concentration of bromine gas is 0.00135 M

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

                   2BrCl\rightleftharpoons Br_2+Cl_2

<u>Initial:</u>          0.02               0.03

<u>At eqllm:</u>    0.02-2x     x     0.03+x

The expression of K_c for above equation follows:

K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}

We are given:

K_c=0.141

Putting values in above equation, we get:

0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

8 0
3 years ago
Other questions:
  • What mass of manganese(II) chloride must react with sulfuric acid to release 52.5 mL of hydrogen chloride gas at STP?
    12·1 answer
  • What equation allows you to calculate the force on an object
    15·2 answers
  • The amount of water vapor in the air, compared to the maximum amount that can be held at a specific air temperature is called:
    15·1 answer
  • 1. The "3" in 3 CaCl2 is called the:
    12·1 answer
  • What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a<br> 0.75 L solution? *
    11·2 answers
  • After the child exhaled all of the gas, it becomes sick
    12·2 answers
  • 10. Which statement is the most important reason that some people feel that solar energy power can be a pollution-free energy so
    14·1 answer
  • How many atoms are in 1.4 moles of H3PO4?
    9·1 answer
  • A balance was tested against a standard calibration mass with a certified value of 200.002 g and produced the following readings
    10·1 answer
  • What is the chemistry​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!