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Tema [17]
3 years ago
13

How many moles of helium are needed to fill a balloon to a volume of 5.3 L at 22 ℃ and 632 mmHg?

Chemistry
1 answer:
son4ous [18]3 years ago
6 0

Answer:

0.18 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm,  R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (0.8316×5.3)/(0.083×295)

n = 0.18 moles

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Sulfuric acid in water dissociates completely into H+ and HSO4− ions. The HSO4− ion dissociates to a limited extent into H+ and
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Answer:

0.0010m SO₄²⁻

Explanation:

The freezing point depression due the addition of a solute into a pure solvent follows the equation:

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Van't Hoff factor could be understood as  in how many one mole of the solute (sulfuric acid, H₂SO₄), is dissociated.

H₂SO₄ dissociates as follows:

H₂SO₄ → HSO₄⁻ + H⁺

HSO₄⁻ ⇄ SO₄²⁻ + H⁺

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1 Mole of H₂SO₄ dissociates in 1 mole of H⁺+ 1 mole of HSO₄⁻ + X moles of   SO₄²⁻= 2 + X

Replacing in (1):

0.68°C = 1.86°C/m×0.1778m×i

2.056 = i

Moles of SO₄²⁻ are 2.056 - 2 = 0.056moles SO₄²⁻.

If 1 mole has a concentration of 0.1778m, 0.056moles are:

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C. Energy is absorbed and released during chemical reactions,

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