All categories

3 years ago

What is the electron structure of a sodium atom?

Chemistry

2 answers:

CaHeK987 [17]3 years ago

8 0

There are 11 electrons in Sodium ( find this on the periodic table).

Then you need to arrange the electrons in the orbitals around the nucleus.

The structure would be written as A. 1s^22s^22p^63s^1

nordsb [41]3 years ago

7 0

Answer:

1s22s22p63s1 is the electronic configuration of sodium.

Explanation:

You might be interested in

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Julli [10]

Answer:

The number of molecules.

Explanation:

7 0

3 years ago

It says draw a ring around all the objects that will be attracted to a magnet the one there are : a 2p coin,cobalt,an aluminium

Katen [24]

Answer: do

Explanation:

5 0

2 years ago

Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)

marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

$S.G=\frac{D}{d_w}$

$d_w$ = density of water = 1 g/mL

$D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL$

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = $\frac{Mass}{Density}$

$=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L$

1 mL = 0.001 L

$Molarity = \frac{n}{V(L)}$

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

$Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L$

5 0

2 years ago

A hydrogen halide diffuses 1.49 times faster than HBr. This hydrogen halide is

marysya [2.9K]

To solve this problem, we must assume ideal gas behaviour so that we can use Graham’s law:

vA / vB = sqrt (MW_B / MW_A)

where,

<span>vA = speed of diffusion of A (HBR)</span>

vB = speed of diffusion of B (unknown)

MW_B = molecular weight of B (unkown)

MW_A = molar weight of HBr = 80.91 amu

We know from the given that:

vA / vB = 1 / 1.49

So,

1/1.49 = sqrt (MW_B / 80.91)

MW_B = 36.44 g/mol

Since this unknown is also hydrogen halide, therefore this must be in the form of HX.

HX = 36.44 g/mol , therefore:

x = 35.44 g/mol

From the Periodic Table, Chlorine (Cl) has a molar mass of 35.44 g/mol. Therefore the hydrogen halide is:

HCl

6 0

3 years ago

How many moles of CO2 are there in 8.91 x 1023 molecules of CO2?<br> (1 mole= 6.02 x 1023)

Karo-lina-s [1.5K]

Answer:

<h2>1.48 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.91 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{8.91}{6.02} \\ = 1.480066...$

We have the final answer as

<h3>1.48 moles</h3>

Hope this helps you

6 0

3 years ago