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Andrews [41]
3 years ago
11

Which type of energy is converted when gasoline burns in an engine?

Physics
2 answers:
vladimir1956 [14]3 years ago
5 0
The answer is C) chemical potential energy. Fire is a chemical reaction.
never [62]3 years ago
4 0

Answer:

The answer is c) chemical potencial energy

Explanation:

The <em>elastic potencial energy</em>  is the energy that results from applying a force to deform an elastic object, for example a spring that can be compressed or stretched.

Atoms are the smallest particles into which a chemical element can be divided. In the nucleus of each atom there are two types of particles: neutrons and protons. <em>Nuclear potential energy</em> is the energy that is in the nucleus and holds together protons and neutrons.

The <em>gravitational potential energy</em> is the energy that a body has when it is under the action of gravity. For example, if you drop a tennis ball at a certain height from the ground, you will observe that it will fall and hit the ground. This is due to the action of gravity.

And finally, the <u><em> chemical potential energy</em></u> is the energy present in a chemical reaction, where the reagents absorb or release energy when transformed into products. When gasoline burns in an engine, combustion is taking place, that is, a chemical process.  So, this is the type of energy that is converted when gasoline burns.

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A patient is given 40.00 mg of iodine-131 (131I ) 131 53
N76 [4]
<h3>Answer:</h3>

2.5 mg

<h3>Explanation:</h3>

<u>We are given</u>;

  • Original mass of I-131 is 40.0 mg
  • Half life of I-131 is 8 days
  • Number of days 32 days

We are required to determine the mass that will remain;

  • Using the formula;

N = N₀ × 0.5^n

where, N is the remaining mass, N₀ is the original mass, and n is the number of half lives.

Therefore;

n = time ÷ half life

   = 32 days ÷ 8 days

  = 4

Therefore;

Remaining mass = 40.0 mg × 0.5^4

                            = 2.5 mg

Hence, the remaining mass of I-131 after 32 days is 2.5 mg

5 0
3 years ago
A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine
Free_Kalibri [48]
500 but I could be wrong go with your gut my dude
6 0
3 years ago
Read 2 more answers
Two blocks with masses m1=0.25kg and m2=1.4kg approach each other along a horizontal, frictionless track. The initial velocities
Alina [70]

Answer:

The energy would remain equal to that of the initial kinetic energy since it is a frictionless surface. However if it is an inelastic collision then energy would be lost due to sound and heat.

Explanation:

4 0
4 years ago
Which form of the energy is used to generate electrical energy in a tidal power station
Alla [95]

Tidal energy is the form of energy used to generate electrical energy.

7 0
3 years ago
A) A wire made from iron with a cross-section of diameter 0.800 mm carries a current of 14.0 A. Calculate the "areal current den
Veseljchak [2.6K]

Answer:

A) ρ=1.74x10^{26}

B) μ=1.68x10^{29}\frac{electron}{m^3}

C) v=1.03x10^{-3}\frac{m}{s}

D)e=8.99x10^-9

Explanation:

A)

The magnetic field can be find knowing the current is the charge per second

β= \frac{14eC*s}{1.6x10^{-19}C}\\

β= 8.75x10^{19}e*s

Electron density

ρ=\frac{8.75x10^{19}}{\pi*0.400x10^{-3}m} = 1.74x10^{26}

B)

μ= \frac{7.86}{56.2}\frac{g}{cm^3} \frac{mol}{g}*6.022x10^{23}\frac{molecules}{mol} *2 \frac{electron}{molecule}

μ=1.68x10^{23} \frac{electron}{cm^3}= 1.68x10^{29} \frac{electron}{m^3}

C)

The drift speed using last information found

v= \frac{J}{n*q} \\v= \frac{14A}{\pi*((0.40x10^-3)^2)*1.68x10^29*1.60x10^-19)} = 1.03x10^-3(\frac{m}{s} )

D)

To compared the random thermal motion and the current's drift speed

e=\frac{1.03x10^-3}{1.15x10^5} = 8.99x10^-9

8 0
3 years ago
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