All categories

3 years ago

Which compound is composed of oppositely charged ions?

Physics

1 answer:

zhuklara [117]3 years ago

8 0

Answer:

Compound having oppositely charged ions are considered as<em><u> ionic compounds.</u></em>

Explanation:

Compound having oppositely charged ions are considered as ionic compounds.

You might be interested in

Relative density of mercury is 13600 what does it mean

zvonat [6]

Answer:

relative density is the density divided by some reference density.

for liquids like mercury the reference density is most likely water, so

relative density = density mercury / density of water = 13600

8 0

3 years ago

Brainliest for correct answer! :)

Katena32 [7]

Answer:

1. 300.15

2. 873.15

3. 221.95

1. -243.15

2. -210.85

3. 295.17

5 0

3 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Nezavi [6.7K]

Answer: 1.124 m

Explanation:

This situation is a good example of the projectile motion or parabolic motion, and the main equations that will be helpful in this situations are:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=2.80 m/s$ is the initial speed

$\theta=39\°$ is the angle at which the venom was shot

$t$ is the time since the venom is shot until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.4 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Knowing this, let's begin:

First we have to find $t$ from (2):

$0=0.4 m+2.8 m/s sin(39\°) t+\frac{-9.8m/s^{2}t^{2}}{2}$ (3)

Rearranging (3):

$-4.9 m/s^{2} t^{2} + 1.762 m/s t + 0.4 m=0$ (4)

This is a <u>quadratic equation</u> (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9$

$b=1.762$

$c=0.4$

Substituting the known values:

$t=\frac{-1.762 \pm \sqrt{(1.762)^{2} - 4(-4.9)(0.4)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.517 s$ (7)

Substituting (7) in (1):

$x=2.8 m/s cos(39\°) (0.517 s)$ (8)

Finally:

$x=1.124 m$ (9)

4 0

4 years ago

The ______ length of a lens is the distance from the center of the lens to<br> its principal focus.

Marizza181 [45]

Answer:

<h2>Focal length</h2>

Explanation:

The Focal length of a lens is the distance from the center of the lens to

its principal focus.

3 0

3 years ago

A cylindrical piece of wood of height H, radius r, and uniform density rhoc is bobbing up and down in still water with its axis

Keith_Richards [23]

Answer:

$r\sqrt{\frac{g\pi\rho_w}{m}}$

Explanation:

As the buoyant force is proportional to the length of which the wood is submerged in water, we can model the buoyant force as a spring force and the bobbing wood is a simple harmonic motion described as A cos (ωt + φ) where

$\omega = \sqrt{\frac{k}{m}}$