The answer would be D) the building center of a spiral galaxy consisting of stars in the shape of a flattened sphere that circles a black hole
As air heats up, air molecules occupy a larger area comparitively to cool air. To summerize, the ball will appear to be "more inflated."
Answer:
x₁ = 0.62 m
Explanation:
In this exercise the force is electric, given by Coulomb's law
F =
This force is a vector, since the three charges are in a line we can reduce the vector sum to a scalar sum.
For the sense of force let us use that charges of the same sign repel and charges of the opposite sign attract.
∑ F = F₁₂ - F₂₃
They ask us to find the point where the summaries of the force is zero.
F₁₂ - F₂₃ = 0
F₁₂ = F₂₃
let's fix a reference system located in the first charge (more to the left), the distance between the two charges is d = 1.5 m and x is the distance to the location of the second sphere
k q₁q₂ / x² = k q₂q₃ / (d-x) ²
q₁ (d-x) ² = q₃ x²
let's solve
d² - 2 x d + x² =
x²
x² (1 -
) - 2x d + d² = 0
we substitute the values
x² (1- 4/2) - 2 1.5 x + 1.5² = 0
x² (-1) - 3.0 x + 2.25 = 0
x² + 3 x - 2.25 = 0
let's solve the quadratic equation
x = [-3 ±
] / 2
x = [-3 ± 4.24] / 2
x₁ = 0.62 m
x₂ = 3.62 m
since it indicates that the charge q₂ e places between the spheres, the correct solution is
x₁ = 0.62 m
The Joule is the SI unit of energy.
Answer:
+ 0.07 C
Explanation:
From the question given above, the following data were obtained:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
The energy (E) , potential difference (V) and charge (Q) are related by the following equation:
E = ½QV
With the above formula, we can obtain the charge as follow:
Potential difference (V) = 12 V
Energy (E) = 0.418 J
Charge (Q) =?
E = ½QV
0.418 = ½ × Q × 12
0.418 = Q × 6
Divide both side by 6
Q = 0.418 / 6
Q = + 0.07 C