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Free_Kalibri [48]
2 years ago
14

Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of

3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2)
19.5 km/s


27.5 km/s


11.2 km/s


20.5 km/s
Physics
1 answer:
Bad White [126]2 years ago
5 0

The orbital speed of an ice cube in the rings of Saturn is 355358.97m/s

<h3>Law of gravitation</h3>

According to the gravitation law, the force of gravitation is directly proportional to the product of the masses and inversely proportional to the distance between them. Mathematically;

F = GMm/r²

where

m = mass of ice cube and

s = Gm1/r^2

Hence,

F = sm2

On rearranging,

s = m2/F

let V = orbital speed

centripetal acceleration = V^2/r

Such that;

V²/r = Gm/r²

V² = Gm/r

V = √Gm/r

Substitute the given parameters

V =  √6.67×10^-11 *  5.68 x 10^26 / 3.00 x 10^5

V = 355358.97m/s

Hence the orbital speed of an ice cube in the rings of Saturn is 355358.97m/s

Learn more on orbital speed here: brainly.com/question/22247460

#SPJ1

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The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if
m_a_m_a [10]

Answer:

Required energy = 4758 J

Explanation:

Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).    

Given data :

Specific heat capacity = c = 2440 J/kg.°C

Mass = m = 150 g = 0.15 kg

Initial temperature = 22°C

Final temperature = 35°C

Change in Temperature = ΔT = 13°C

Energy = E = ?

Using the following formula and substituting the values, we get:

E = m × c × ΔT

E = 0.15 × 2440 × 13

E = 4758 J

8 0
3 years ago
Newton’s Second law of Motion (F = ma) is one of the basis of forces and motion. How is it very similar to his First law and why
koban [17]

Answer:

First law can be deduced from second law.

Acceleration may determine the position and velocity of the system.

Explanation:

When net force is zero, the second law is 0 = ma, or the motion is at constant speed. Thus first law establishes that when there are no forces, the object moves at constant speed, so first law is explained by using the second.

If you determine the acceleration of a system, you may use calculus or kinematic equations to determine velocity and position of the particle and determine how it moves. This is very important in mechanics and engineering, for example, for spacecrafts, forensic situations, etc.

4 0
3 years ago
Four 240 Ω light-bulbs are connected in series. What is the total resistance of the circuit? What is their resistance if they ar
irina [24]

Had to submit as image as it wouldn't let me paste these symbols in the answer box

hope this helps:)

5 0
3 years ago
Bird bones have air pockets in them to reduce their weight–this also gives them an average density significantly less than that
lakkis [162]

Answer:

a)39ml

b)39g

c)1.1g/ml

Explanation:

Hello!

To solve this exercise use the following steps

1. When Archimedes discovered how to determine the irregular volume of an object by weighing it in the air and in an algua, he found that its volume is equal to the ratio between the differences of the masses (heavy in the air and in the water) and the density of the water (= 1g / ml)

V=\frac{43g-3.6g}{1g/ml} =39.4ml

2.as the principle of archimedes says, the displaced volume of water is equal to the volume of the bone which means that 39.4ml of water was displaced, taking into account that the density of water is the ratio between mass and volume we can determine the displaced body of water

density=\frac{m}{V} \\m=V(density)\\m=(39ml)(1g/ml)=39g

3. we use the density equation to find the bone density

density=\frac{43g}{39ml} =1.1g/ml

8 0
3 years ago
Compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 10
DochEvi [55]

Answer:

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

Explanation:

Let's start by calculating each force.

Gravitational force

             F =G \frac{m_1m_2}{r^2}  

let's calculate

             F = 6.67 10⁻¹¹  1  1 / 1²

             F = 6.67 10⁻¹¹ N

Electric force

             F = k \frac{q_1q_2}{r^2}  

indicates that the charge is q = 10 C

            F = 9 10⁹ 10 10 / 1²

            F = 9 10¹¹ N

Let's see the similarities between the two forces

* are proportional to the product of a magnitude, mass or charge

* They are inversely proportional to the square of the distance

* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.

The differences in them

* The electric force in much greater than the gravitational force

* The gravitational force is always attractive, the electrical force can be attractive or repulsive.

3 0
3 years ago
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