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4 years ago

(45.22 – 73.91) – |65.85 – 79.15|

Mathematics

1 answer:

DerKrebs [107]4 years ago

8 0

B. -41.99 is your answer.

Hope this helps & good luck. :)

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What’s the correct answer for this question?

crimeas [40]

ANSWER

EXPLANATION

The given line has slope,

and

We can find the equation in the point slope form, which is given by,

We substitute the point and slope to get,

We can also simplify further to get,

We make y the subject to get,

This is called the slope intercept form.

We could also write in standard form to get

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3 years ago

A lorry travel at 30 km per hour.If it takes 3/4 hour for a certain journey,how long is that journey

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Answer:

22.5 km

Step-by-step explanation:

divide 30 by 4 times it by 3

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2 years ago

Solve for the value of p.<br> (6p-2)<br> न<br> (3p-7)|

Westkost [7]

Answer:

The sum of angles on a straight line is 180 degrees.

Therefore,

$(6p-2)+(3p-7)=180$

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2 years ago

Using the slope formula, find the slope of the line through the given points ( 9, 4 ) and ( 4, 4 )

irakobra [83]

Answer: 0

Step-by-step explanation: it’s undefined

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3 years ago

Read 2 more answers

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

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3 years ago