The given equation of parabola is
Which can also be written as
Here vertex (h,k) is (1,2)
And value of a is
Formula of focus is
Substituting the values of h,k and a, we will get
Therefore the correct option is the last option .
Explanation:
All of these are done the same way.
1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.
2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".
3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".
4. A line through the original point and point R will be perpendicular to the line, as you want.
_____
In problem 1, the point and line are obvious.
In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)
1st quartile (25%) and the 3rd quartile (75%) values are -0.6745 and 0.6745 respectively. Use this formula z= (x-mean)SD -0.6745 = (x-25.3)/6.5.
x=25.3 - 0.6745(6.5) = 25.3 - 4.3843 = 20.9157 1st Quartile
0.6745 = (x - 25.3) 6.5
x = 25.3 + 0.6745 = 25.3 + 4.3843 = 29.6843 3rd quartile
interquartile range is the difference between the 1st quartile and the 4th quartile
Answer:
89
Step-by-step explanation:
Given that the class has 28 students has 7 juniors and 21 seniors
mean score of the juniors = 73
Therefore, total score of junior = 73 × 7
= 511
mean score of seniors = y
Total score of seniors = 21y
Total score of the class = 511 + 21y
Mean score of the class = 85
Total score of the class = 85 × 28
= 2380
therefore,
511 + 21y = 2380
21y = 2380 -511
21y = 1869
y = 1869/21
y = 89
Answer:
3, 4, -7
Step-by-step explanation:
Coefficients are the numbers in front of the variable.
