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MissTica
3 years ago
10

Consider a cylinder with a radius of 6 ft and height of 11.5

Mathematics
1 answer:
maria [59]3 years ago
6 0
The formula for a cylinder V= pi r squared times the height. I should suppose you were told to abbreviate pi to 3.14. First do 6 to the power of 2 which is 36 then multiply it by 3.14 witch would be 113.04. Then multiply that by 11.5 which would be 1299.96

The answer is 1299.96
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R2+2r-33=0 solve by completing the square
-BARSIC- [3]
R^2+2r-33=0  move constant to other side by adding 33 to both sides

r^2+2r=33   halve the linear coefficient, square it and add to both sides, in this case it is just one

r^2+2r+1=34  now the left side is a perfect square...

(r+1)^2=34  take the square root of both sides...

r+1=34^(1/2)  subtract 1 from both sides

r=-1+34^(1/2) and -1-34^(1/2)
8 0
3 years ago
Western Athletic Club International (WACI) owns and operates a chain of fitness clubs. Currently WACI has 675 members at its Col
Ad libitum [116K]

Answer:

12%

Step-by-step explanation:

let x represent the actual number of members last year.

current members = 675 and with an increment of 13% over previous year

to find the increment

(675 - x) / x = 0.13

675 - x = 0.13x

collect the like terms

675 = 0.13x + x

675 = 1.13 x

x = approx 597 members were there last year

its hope to increase by the same number next year

percent increase = 675 - 597 / 675 = 78 / 675 = 0.12 = 12%

4 0
3 years ago
On a coordinate plane, the x-coordinate is negative and the y-coordinate is positive in which quadrant?
Nataly [62]
When x is lesser than 0
6 0
3 years ago
Help plz find the equation​
tatiyna

                                              Question # 1

Step-by-step Explanation:

Given

\frac{1}{2}\div \frac{2}{3}

solving

\frac{1}{2}\div \frac{2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{1}{2}\times \frac{3}{2}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{1\times \:3}{2\times \:2}

\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3

=\frac{3}{2\times \:2}

\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4

=\frac{3}{4}

Therefore, completing the blanks:

\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}

                                             Question # 3

Step-by-step Explanation:

Given

\frac{2}{5}\div \frac{3}{4}

solving

\frac{2}{5}\div \frac{3}{4}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2}{5}\times \frac{4}{3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2\times \:4}{5\times \:3}

\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8

=\frac{8}{5\times \:3}

\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15

=\frac{8}{15}

Therefore, completing the blanks:

\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}

                                                Question # 5

Step-by-step Explanation:

Given

\frac{3}{4}\div \frac{5}{7}

solving

\frac{3}{4}\div \frac{5}{7}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{3}{4}\times \frac{7}{5}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{3\times \:7}{4\times \:5}

\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21

=\frac{21}{4\times \:5}

\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20

=\frac{21}{20}

Therefore, completing the blanks:

\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}

6 0
3 years ago
Factor completely 15x2 - 6x + 5xy – 2y
vagabundo [1.1K]

The complete factorization of 15x² - 6x + 5xy - 2y is (5x - 2)(3x + y)

Step-by-step explanation:

If we have an expression of four terms, then we factorize it by using

the grouping factorization

In grouping factorization we do that

1. Collect each two terms with common factors into 2 brackets

2. Take the common factor from each bracket, which make the brackets

    equal each other

3. Take the bracket as a common factor, the answer will be 2 factors

    multiply by each other

∵ The expression is 15x² - 6x + 5xy - 2y

- Take the first 2 terms in a bracket and the last 2 terms in another

  bracket

∴ (15x² - 6x) + (5xy - 2y)

∵ The common factor of 15x² and 6x is 3x

- Divide each term by 3x

∵ 15x² ÷ 3x = 5x

∵ 6x ÷ 3x = 2

∴ (15x² - 6x) = 3x(5x - 2)

∵ The common factor of 5xy and 2y is y

- Divide each term by the common factor y

∵ 5xy ÷ y = 5x

∴ 2y ÷ y = 2

∴ (5xy - 2y) = y(5x - 2)

∴ (15x² - 6x) + (5xy - 2y) = 3x(5x - 2) + y(5x - 2)

∵ The bracket (5x - 2) is a common factor of the two terms

- Divide each term by the common factor (5x - 2)

∵ 3x(5x - 2) ÷ (5x - 2) = 3x

∵ y(5x - 2) ÷ (5x - 2) = y

∴ 3x(5x - 2) + y(5x - 2) = (5x - 2)(3x + y)

∴ 15x² - 6x + 5xy - 2y = (5x - 2)(3x + y)

The complete factorization of 15x² - 6x + 5xy - 2y is (5x - 2)(3x + y)

Learn more:

You can learn more about the factors in brainly.com/question/10771256

#LearnwithBrainly

4 0
3 years ago
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