The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
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x+y=8 and 25x+10y=170 are the linear equations.
x+y≤8 and 25x+10y≤170 are the inequalities.
Step-by-step explanation:
Given,
Worth of coins = $1.70 = 1.70*100 = 170 cents
Number of coins = 8
1 quarter = 25 cents
1 dime = 10 cents
Let,
x represent the number of quarters
y represent the number of dimes
1. Write an equation to represent the amount of coins Karen has.
x+y = 8
2.Write an equation to represent the value of the coins Karen has.
25x+10y=170
x+y=8 and 25x+10y=170 are the linear equations.
For inequalities, the amount cannot increase number of coins and worth but it can be less, therefore,
x+y≤8
25x+10y≤170
x+y≤8 and 25x+10y≤170 are the inequalities.
Keywords: linear equations, addition
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