From greatest to least it goes |-34| , |26| , -|-20| , -23 , -|28|
Answer:
i think it is answer choice 2
Step-by-step explanation:
it is the only answer that works with the reciprocal
Answer:
5/18
Step-by-step explanation:
1/3 on monday
5/6 more
1/3 times 5/6
A]
Amount of earning per hour=$8.59
Amount of David's benefits=18/100×8.59=:1.5462
Amount that David earn per hour including benefits is given by:
8.59+1.5462=$10.1362
b]Amount that David earns in 35 hour a week will be:
(amount per hour)*(number of hours)
=8.59*35
=$$300.65
C] amount earned by David including benefits will be:
(amount earned in 35 hours)+(total benefits in 35 hours)
total benefits=1.5462×35=$54.117
thus total amount will be:
300.65+54.117
=$354.767
Answer:
Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:
Where
and
Since the distribution of X is normal then we know that the distribution for the sample mean
is given by:
And we have;


Step-by-step explanation:
Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of
Round your answers to two decimal places.
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:
Where
and
Since the distribution of X is normal then we know that the distribution for the sample mean
is given by:
And we have;

