What did Tyler do wrong?

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

7 0

He made and error in the third step by not distributing the -4

THe correct way would be:

9+(-4)(5x-6)

9-20x+24

-20x+33

You might be interested in

Work out m and c for the line: ? y = x + 6

lapo4ka [179]

Well your c value is already there (6) as the standard equation for a line is
y = mx + c

To find the gradient (M) plot two points on the line.

Then label each co ordinate X1 and X2 and then Y1 and Y2

Then subtract your y1 from y2 and then x1 from x2.

For example :if your coordinates were (1,2) (3,4) you would do
4-2 and 3-1

These answers become your “changes” now do change in y / change in x

In terms of the Example you would do 2/2 which would be 1 and the M value would be 1

Hope that isn’t too confusing

7 0

3 years ago

PLEASE HELP ME ASAP ITS DUE AT MIDNIGHT AND I DONT HAVE A LOT OF TIME

Ne4ueva [31]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa

zalisa [80]

Answer:

The students have to score 0.74 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

A random variable X is said to have a normal distribution with parameters µ (mean) and σ² (variance).

If $X \sim N (\mu, \sigma^{2})$ , then $z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

The distribution of these z-scores is known as the standard normal distribution.

The z-score is a standardized form of the raw score, X. It is a numerical measurement of the relationship between a value (X) and the mean (µ) in terms of the standard deviation (σ). A z-score of -1 implies that the data value is 1 standard deviation below the mean. And a z-score of 1 implies that the data value is 1 standard deviation above the mean.

Let X be defined as the scores of students at the National Financial Capability Challenge Exam.

It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.

That is, P (X > x) = 0.23.

⇒ $P(\frac{X-\mu}{\sigma}>\frac{x-\mu}{\sigma})=0.23$