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Maslowich
3 years ago
5

Dory bought a sandwich for $6.75 a bag of dried fruit for $1.45 and a bottle of water for $1.75. She paid the cashier with the $

20 bill. how much change did she receive?
Mathematics
1 answer:
Alla [95]3 years ago
5 0
$6.75+$1.45+$1.75=$9.95
$20-$9.95=$10.05
Answer: Dory received $10.05 in change.
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A car traveled 385 miles in 7 hours.It traveled the same number of miles each hour.If the car continues at the same number of mi
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Step-by-step explanation:

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A bag of marbles contains 28 red marbles, 30 green marbles, and 24 yellow marbles. What is the ratio of red marbles to yellow ma
Basile [38]

Answer:

The answer to your question is 7:6

Step-by-step explanation:

Data

Number of red marbles = 28

Number of green marbles = 30

Number of yellow marbles = 24

Radio = ?

Process

1.- Write the ratio

                   Red marbles : Yellow marbles

2.- Substitution

                                  28 : 24

3.- Simplification

-Divide both terms by 2

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-Divide by two both terms

                                    7 : 6

-It is not possible to simplify more.

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

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