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Vika [28.1K]
4 years ago
13

Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106M O2, 0.00652M SO3, and 0.00129M S

O2. Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106 M O2, 0.00652 M SO3, and 0.00129 M SO2.
2 SO3 (g) ⇌ 2 SO2 (g)+O2(g)

(a)1.34 × 10^-2
(b)6.78 × 10^-2
(c)4.15 × 10^-3
(d)4.35 × 10^-2
Chemistry
1 answer:
malfutka [58]4 years ago
6 0

equilibrium constant K = 4.15 × 10⁻³

Explanation:

We have the following chemical equilibrium:

2 SO₃ (g) ⇄ 2 SO₂ (g) + O₂ (g)

equilibrium constant K = ( [SO₂]² × [O₂] ) / [SO₃]²

equilibrium constant K = ( 0.00129² × 0.106 ) / 0.00652²

equilibrium constant K = 0.414 × 10⁻² = 4.14 × 10⁻³ ≈ 4.15 × 10⁻³

Learn more about:

equilibrium constant

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A gas has a mass of 3.82 g and occupies a volume of 0.854 L. The temperature in the laboratory is 302 K, and the air pressure is
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The molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.

<h3>How to calculate molar mass?</h3>

The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.

However, the number of moles of the gas in this question needs to be calculated first using the ideal gas law equation:

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