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Vika [28.1K]
4 years ago
13

Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106M O2, 0.00652M SO3, and 0.00129M S

O2. Calculate the equilibrium constant for the reaction below if a tank was found to contain 0.106 M O2, 0.00652 M SO3, and 0.00129 M SO2.
2 SO3 (g) ⇌ 2 SO2 (g)+O2(g)

(a)1.34 × 10^-2
(b)6.78 × 10^-2
(c)4.15 × 10^-3
(d)4.35 × 10^-2
Chemistry
1 answer:
malfutka [58]4 years ago
6 0

equilibrium constant K = 4.15 × 10⁻³

Explanation:

We have the following chemical equilibrium:

2 SO₃ (g) ⇄ 2 SO₂ (g) + O₂ (g)

equilibrium constant K = ( [SO₂]² × [O₂] ) / [SO₃]²

equilibrium constant K = ( 0.00129² × 0.106 ) / 0.00652²

equilibrium constant K = 0.414 × 10⁻² = 4.14 × 10⁻³ ≈ 4.15 × 10⁻³

Learn more about:

equilibrium constant

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How many molecules are there in 3.5 moles of carbon dioxide? A. 63.21 x 10^23 B. 21.07 x 10^23 C. 42.14 x 10^23 D. 6.02 x 10^23
Alik [6]

Answer:

B. 21.07 x 10²³ molecules

Explanation:

Avogadro's Number: 6.022 x 10²³

Step 1: Set up equation

3.5 mols CO_2(\frac{6.022(10^{23}) moleculesCO_2}{1 mol CO_2})

Step 2: Multiply and cancel out units

3.5(6.022 x 10²³) = 21.07 x 10²³ molecules CO₂

Step 3: Convert to proper scientific notation

≈ 2.11 x 10²³ molecules CO₂

5 0
3 years ago
Convert the following into balanced equations:
masya89 [10]

Balanced equation :

2C₆H₁₄  + 19O₂  → 12CO₂ + 14H₂O

Organic Nomenclature:

Hexane is a six-carbon straight-chain alkane. The prefix "hex-" signifies the number 6 for alkanes, and the suffix "-ane" is what clarifies that this hydrocarbon has only carbon-carbon single bonds. There are no double or triple bonds.

Elaborating the equation :

The mass of hexane available for this reaction is converted to a quantity of moles by multiplying by its density to get a mass and then dividing by its molar mass. This quantity of moles is then related to the quantity of moles of oxygen by their molar ratios. According to this balanced reaction equation, every 2 moles of hexane burned will require the reaction of 19 moles of oxygen gas.

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5 0
2 years ago
Be sure to answer all parts. What can be added to the equilibrium AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2+(aq) + Cl−(aq) (a) that will shi
lora16 [44]

Answer:

a) Ag(NH₃)₂⁺,  Cl⁻.

b) NH₃.

c) AgCl.

Explanation:

Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.

In the reaction:

AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)

When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:

a) Ag(NH₃)₂⁺,  Cl⁻. The addition of products will shift the equilibrium to the left

b) NH₃. The addition of reactant will shift the equilibrium to the right.

c) As AgCl is in solid phase, will not shift the equilibrium in either direction.

6 0
4 years ago
A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

7 0
3 years ago
When neutrons are added to the atom, the mass number
lianna [129]
The answer is 3) no change

Hope this helps
4 0
3 years ago
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