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Brilliant_brown [7]
3 years ago
15

I'm giving 50 points and brainliest answer to whoever can answer this... Please show your work so I can try to understand it xD

<3

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0
Ok, to solve this first you have to set up your proportion:

9/150=x/230

/ is a fraction

x= the number of vials it will take to treat 230 patients

in order to solve this, you have to cross multiply:

9 x 230= 2070

150 · x= 150x

so you get 150x=2070

then divide 2070 by 150

2070/150= 13.8

so it would take 13.8 vials of medicine to treat 230 patients
cluponka [151]3 years ago
4 0
<span>Okay, firstly, you want to work out how many people will 1 vial of malaria treat. So, you do this: 

150 divided by 9= </span><span>16.6

</span><span>That means for every 1 vial, 16.6 people are treated.
</span>
<span>Since the question asks you to find out how many vials are needed if you're required to treat 230 people, you would do this:
</span>
230 divided by 16.6= <span>13.8

</span>That means you need 13.8 vials to treat 230 people.
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Answer:

a. Probability of Event A = 2.724037476607E−24

b. G19 = 0.123

c. P(Winning) = 0.475

Step-by-step explanation:

Given

Red (r) = 19

Green (g) = 19

Black (b) = 2

Total = 19 + 19 + 2 = 40

a. In 40 spins of the wheel, find the probability of event A = {19 reds, 19 greens, and 2 blacks}.

This is calculated as follows;

Let P(R) = Probability of Red

P(R) = 19/40

Let P(G) = Probability of Green

P(G) = 19/40

Let P(B) = Probability of Black

P(B) = 2/40

Total number of arrangement = 40!/(19!19!2!) = 27,569,305,764,000

Probability of Event A = 27,569,305,764,000 * (19/40)^19 * (19/40)^19 * (2/40)^19

Probability of Event A = 2.724037476607E−24

b. In 40 spins of the wheel, find the probability of the event G19 = {19 greens}.

Let P(G) = Probability of Green

P(G) = 19/40

Let P(Other) = Probability of any colour other than green = (2+19)/40

P(Other) = 21/40

Total = 40C19

G19 = 40C19 * (19/40)^19 * (21/40)^21

G19 = 0.125525075056335

G19 = 0.123 ---- Approximated

c. Given that you randomly choose to bet red and green only, what is the probability p that you bet a winner?

Let P(R) = Probability of Betting Red

P(R) = 19/40

Let P(G) = Probability of Betting Green

P(G) = 19/40

Let P(Winning) = Probability of Winning

P(Winning) = ½ * P(G) + ½ * P(R)

P(Winning) = ½ * 19/40 + ½ * 19/40

P(Winning) = ½(19/40 + 19/40)

P(Winning) = ½(38/40)

P(Winning) = 19/40

P(Winning) = 0.475

7 0
3 years ago
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Answer:

$133.77

I am pretty sure that this is the answer.

Step-by-step explanation:

1 + (1.25)^29 = 646.23

200 + (20 x 29) = 780

780 - 646.23 = 133.77

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larisa [96]

Answer:

a) P(X

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P(x

And using the cumulative distribution function we have this:

P(x

And solving for c we got:

c = 20*0.9 = 18

Step-by-step explanation:

For this case we define the random variable X as he amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train, and we know that the distribution for X is given by:

X \sim Unif (a=0, b =20)

Part a

We want this probability:

P(X

And for this case we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} = \frac{x-0}{20-0}= \frac{x}{20}

And using the cumulative distribution function we got:

P(X

For the probability P(X>14) if we use the cumulative distribution function and the complement rule we got:

P(X>14) = 1-P(X

Part b

We want this probability:

P(7< X

And using the cdf we got:

P(7< X

Part c

We want to find a value c who satisfy this condition:

P(x

And using the cumulative distribution function we have this:

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c = 20*0.9 = 18

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3:4 = 15:20. True OR False?
7nadin3 [17]
True.
3 x 5 = 15
4 x 5 = 20

Therefore, 3:4 = 15:20

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