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Luba_88 [7]
3 years ago
15

What is the vertex form of y=7x^2+14x+4

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
3 0
The vertex form is y=7(x+1)²-3 which is vertex form

nekit [7.7K]3 years ago
3 0
= 7(x^2 + 2x) + 4

= 7[(x + 1)^2 - 1)] + 4

= 7(x + 1)^2 - 3 (answer)
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Solve the inequality 1/2c > -1​
Alexxandr [17]

Answer:

\frac{1}{2} c >  - 1

c >  - 1 \div  \frac{1}{2}

c >  - 1 \times 2

c >  - 2

6 0
3 years ago
The larger number is 18 more than twice the smaller.if the sum of the two numbers is 93,find both numbers
kodGreya [7K]

Answer:

I believe the numbers are 25 and 68.

Step-by-step explanation:

25 is the smaller number, 25 x 2 = 50, 50 + 18 = 68, and 68 + 25 = 93.

3 0
4 years ago
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3x+5=5x-3
madam [21]

answer= d Step-by-step explanation:

6 0
3 years ago
If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
slega [8]
The given function are
r(x) = 2 - x²    and     w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
            = 2x - x³ - 4 + 2x²

∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>

<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>

8 0
3 years ago
Read 2 more answers
a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long
QveST [7]

Answer:

10.1 years.

Step-by-step explanation:

It is given that,

Principal = 9000

Rate of interest = 5%

No. of times interest compounded = 2 times in an year

Amount after certain time = 14800

The formula for amount:

A=P(1+\frac{r}{n})^{nt}

where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.

Substitute the given values in the above formula.

14800=9000(1+\frac{0.05}{2})^{2t}

\frac{14800}{9000}=(1+0.025)^{2t}

1.644=(1.025)^{2t}

Taking log both sides.

\log(1.644)=\log(1.025)^{2t}

\log(1.644)=2t\log(1.025)    [\because \log a^b=b\log a]

\frac{\log(1.644)}{2\log(1.025)}=t

t=10.066

t=10.1

Therefore, the required time is 10.1 years.

3 0
3 years ago
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