<span>6.37x10^-30 coulomb-meters
The unit for dipole moments is the Debye which is 1x10^-21 C*m^2/s divided by the speed of light (299792458 m/s). So the conversion factor is
1x10^-21 C*m^2/s / 299792458 m/s = 3.33564095E-30 C*m
And converting 1.91 d to Cm gives
1.91 * 3.33564095E-30 C*m = 6.37x10^-30 coulomb-meters</span>
Answer:
2
Explanation:
The pressure at 34ft is the atmospheric pressure (1 atm) plus 1 atm, because at each 34ft the pressure increase by 1 atm, so it will be 2 atm. Let's assume that the lungs will be at a constant temperature, so, by the ideal gas law:
P1*V1 = P2*V2
Where P is the pressure, V is the volume, 1 is the state at 34 ft under the water, and 2 at the water surface, where P2 = 1atm. Thus:
2*V1 = 1*V2
V2 = 2V1
Thus, the volume will change by a factor of 2, so, the volume will double.
Explanation:
I am not understanding your question
Fe(OH)2 exhibits Fe2+, that is easily oxidized by oxigen present in the air.
Fe(OH)2 (green) + H2O - e- = Fe(OH)3 (brown) + H+
this half-reaction shows how Fe(OH)2 is oxidized to yield Fe(OH)3
As it is being oxidized, it loses an electron
O2 (in the air) + 2 H2O + 4 e- = 4 OH-
this half-reaction shows oxygen perfoming its oxidizing properties
You can see that it gains 4 electrons, which he receives from iron (iron loses electron, remember?) So overall electrons are being transferred from iron to oxygen. Iron is oxidized and oxygen is thus reduced.
Since the electrons lost in the first half-equation are the same as the ones gained in the second, lets multiply the first half-equation with the second:
4 Fe(OH)2 (green) + 4 H2O - 4e- = 4Fe(OH)3 (brown)<span> + 4 H+
</span>O2 (in the air) + 2 H2O + 4 e- <span>= 4 OH-
</span>------------------------------
4Fe(OH)2 (green) + O2 (in the air) + 6 H2O + 4 e- - 4 e- = 4Fe(OH)3 (brown) + 4 H+ + <span>4 OH-
</span><span>4 e- - 4 e- = 0
</span>and
4 H+ + <span>4 OH- = 4 H2O
</span>thus
4Fe(OH)2 (green) + O2 (in the air) + 6 H2O<span> = </span>4Fe(OH)3 (brown) + 4 H2O
4Fe(OH)2 (green) + O2 (in the air) + 2 H2O = <span>4Fe(OH)3 (brown)</span>
