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Svetllana [295]
3 years ago
13

Calculate the Cal(kcal) in 1 cup of whole milk: 12 g of carbohydrate, 9 g of fat, and 9 g of protein.

Chemistry
2 answers:
laiz [17]3 years ago
5 0
 Fat: 1 gram = 9 calories    Protein: 1 gram = 4 calories    Carbohydrates: 1 gram = 4 calories    Alcohol: 1 gram = 7 calories"
So, (12 g carbohydrates)*4 Cal=48 Cal; (9 g fat) *9 Cal=81 Cal; (9 g protein)*4 Cal=36 Cal
48 Cal + 81 Cal + 36 Cal = 165 Cal in one glass of milk
enot [183]3 years ago
3 0

Answer:

165Kcal in a cup of whole milk

Explanation:

Hello! Let's solve this!

We know that 1g

carbohydrate = 4 Kcal

1g protein = 4Kcal

1g fat = 9Kcal

We do the conversion of each one

carbohydrates = 12g * 4Kcal * g = 48Kcal

Proteins = 9g * 4Kcal / g = 36Kcal

fat = 9g * 9Kcal / g = 81Kcal

We add all the results to have the total Kcal

48Kcal + 36Kcal + 81Kcal = 165Kcal in a cup of whole milk

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Answer:

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4 0
2 years ago
Any help with these questions would help i'm lost
SSSSS [86.1K]

Answer:

1.  31.25 mL

2.  1.98 g/L

3.  0.45 g/mL

Explanation:

For each of the problems, you need to perform unit conversions.  You need to use the information given to you to convert to a specific unit.

1.  You need volume (mL).  You have density (g/mL) and mass (g).  Divide mass by density.  You will cancel out mL and be left with g.

(50.0 g)/(1.60 g/mL) = 31.25 mL

2.  You are given grams and liters.  You need to find density with units g/L.  This means that you have to divide grams by liters.

(0.891 g)/(0.450 L) = 1.98 g/L

3.  You have to find density again but this time with units g/mL.  Divide the given mass by the volume.

(10.0 g)/(22.0 mL) = 0.45 g/mL

5 0
3 years ago
Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
3 years ago
Ion<br> If we add an electron to a stable element we call it a(n)_____ion<br><br> anion<br> cation
masha68 [24]
The answer is a cation, I may be wrong but cation is plus and anion is subtract
3 0
2 years ago
Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions
lisov135 [29]
D = 0.2 g / ml = 0.2 g / cm³
For example, density of steel is 7.85 g / cm³.
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8 0
3 years ago
Read 2 more answers
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