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Svetllana [295]
4 years ago
13

Calculate the Cal(kcal) in 1 cup of whole milk: 12 g of carbohydrate, 9 g of fat, and 9 g of protein.

Chemistry
2 answers:
laiz [17]4 years ago
5 0
 Fat: 1 gram = 9 calories    Protein: 1 gram = 4 calories    Carbohydrates: 1 gram = 4 calories    Alcohol: 1 gram = 7 calories"
So, (12 g carbohydrates)*4 Cal=48 Cal; (9 g fat) *9 Cal=81 Cal; (9 g protein)*4 Cal=36 Cal
48 Cal + 81 Cal + 36 Cal = 165 Cal in one glass of milk
enot [183]4 years ago
3 0

Answer:

165Kcal in a cup of whole milk

Explanation:

Hello! Let's solve this!

We know that 1g

carbohydrate = 4 Kcal

1g protein = 4Kcal

1g fat = 9Kcal

We do the conversion of each one

carbohydrates = 12g * 4Kcal * g = 48Kcal

Proteins = 9g * 4Kcal / g = 36Kcal

fat = 9g * 9Kcal / g = 81Kcal

We add all the results to have the total Kcal

48Kcal + 36Kcal + 81Kcal = 165Kcal in a cup of whole milk

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3 years ago
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

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3 years ago
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