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3 years ago

It's easiest to weigh------using a balance scale?

Chemistry

1 answer:

allsm [11]3 years ago

3 0

Yes and no it depends if your good at it you could also use a digital scale, but I perferr to use a balance scale

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Balance the combustion reaction between octane and oxygen. 2C8H18 + O2 → CO2 + H2O

LiRa [457]

Answer: 2C8H18 + 25O2 -> 16CO2 + 18H2O

Explanation:

7 0

3 years ago

A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea

Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

The mass of the oil in the cup, is approximately 64.73 grams.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The mass of oil in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

The mass of the oil in the cup, m₁ ≈ 64.73 g

Learn more here:

brainly.com/question/21406849

Possible part of the question obtained from a similar question online, are;

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating = 65.17°C

6 0

3 years ago

How many g are in 2.39kg of magnesium powder

Oliga [24]

Answer:

2.3 Work with the numerator first: 165 mg is 0.165 g. ... 2.9 (a) 1 mg Mo 1 10 3 g

Explanation:

im pretty sure this is the answer

5 0

3 years ago

List the earth names for the 30 alien elements in order of atomic number

adoni [48]

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7 0

4 years ago

what mass of carbon dioxide gas occupies a volume of 81.3 L at 204kPa and a temperature of 95 degrees celcius

pishuonlain [190]

The mass of carbon dioxide will be 238.51g

Explanation:

Given:

Volume, V = 81.3 L

Pressure, P = 204 kPa

P = 204000Pa

Temperature, T = 95°C

T = 95 + 273K

T = 368K

mass of CO₂, m = ?

According to the gas law:

PV = nRT

where, R is the gas constant

n is the moles

and the value of R = 8.314 X 10³ L⋅Pa⋅K⁻¹⋅mol⁻¹

n = m/w

where,

m is the mass of the substance

w is the molecular weight

and molecular weight of CO₂ is 44 g

On substituting the value we get:

$204000 X 81.3 = \frac{m}{44} X 8.314 X 10^3 X 368\\\\m = \frac{204 X 81.3 X 44}{8.314 X 368} \\\\m = 238.51 g$

Therefore, the mass of carbon dioxide will be 238.51g

5 0

3 years ago