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myrzilka [38]
3 years ago
6

Let us say there are five flavors of icecream: banana, chocolate, lemon, strawberry and vanilla. we can have three scoops. how m

any variations will there be?
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0
C(5,3)=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10
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Using principle of mathematical induction prove that 6^-1 divisble by 5 .​
salantis [7]

I suppose the claim is 5 \mid 6^n - 1 for n\in\Bbb N.

When n=1, we have 6^1 - 1 = 6 - 1 = 5, and of course 5 divides 5.

Assume the claim holds for n=k, that 5 \mid 6^k - 1. We want to use this to show it holds for n=k+1, that 5 \mid 6^{k+1} - 1.

We have

6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5

Since 5 \mid 6^k - 1, we can write 6^k - 1 = 5\ell for some integer \ell. Then

6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)

which is clearly divisible by 5. QED

5 0
1 year ago
The 7th-grade class took a survey on their favorite ice cream. 58 people said they prefer vanilla, while 28 people said they pre
MA_775_DIABLO [31]
Since 58 for vanilla and 28 for chocolate
The ratio would be 28:58
You can simplify it even further
to 14:29
6 0
2 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of two errors per page. If more than two
wlad13 [49]

Answer: 0.6767

Step-by-step explanation:

Given : Mean =\lambda=2 errors  per page

Let X be the number of errors in a particular page.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that a randomly selected page does not need to be retyped is given by :-

P(X\leq2)=P(0)+P(1)+P(2)\\\\=(\dfrac{e^{-2}2^0}{0!}+\dfrac{e^{-2}2^1}{1!}+\dfrac{e^{-2}2^2}{2!})\\\\=0.135335283237+0.270670566473+0.270670566473\\\\=0.676676416183\approx0.6767

Hence, the required probability :- 0.6767

6 0
3 years ago
A patient has 0.0000075 gram of iron in 1 liter of blood. The normal level is between 6* 10^-7 grams and 1.6*10^-5 grams. Is the
Vinil7 [7]
0.0000075 = 7.5 x 10^6 --- Patients Blood

and it has to be between 0.0000006 and 0.000016

so <em>Yes</em> it is normal
4 0
3 years ago
Find the absolute value.<br><br> 1 -31=___<br><br> -1 121=___<br><br> -1 -221=___
Veseljchak [2.6K]
I guess we will never know
5 0
2 years ago
Read 2 more answers
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