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2 years ago

Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below.

Mathematics

1 answer:

Alenkinab [10]2 years ago

7 0

Answer:

Probably the 1st picture.

Step-by-step explanation:

keep in mind, the center is 0.

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-91<br> irrational or rational?

Len [333]

Answer:

rational

Step-by-step explanation:

is not an Irrational number because it can be expressed as the quotient of two integers: 91÷ 1

Hope this Helps :)

6 0

2 years ago

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PLEASEE HELP WILL GIVE 100 POINTS AND WILL MARK BRAINLY!

madreJ [45]

I’m pretty sure it’s b because they are camouflaged

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3 years ago

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Robert took $50 with him to spend on pizza and games for himself and his friends at Chuck-E-Cheese the price of each slice of pi

djverab [1.8K]

Half of 5.00 is 2.50, I suppose the 50 is the X in the situation, I don't have a graph to work on sorry I tried to help as much as I can.

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

If the ratio of the length to the breadth of a rectangle be 5:3 and its perimeter is 144m find the length of the rectangle

Kamila [148]

Answer:

length=45 m (2 sides = 90m)

Step-by-step explanation:

5x +3x=144

8x=144

x=18 (each of the 8 parts of 144 measure 18m)

5(18) + 3(18)=144

90 +54=144

90/2=45 (1 length side)

54/2=27 (1 width side)

The rectangle= 45+45 +27+27 = 144

5 0

2 years ago