Answer:
Cost of goods sold is $196
Explanation:
Using FIFO inventory sold are valued at the price of the most earliest stock in inventory.
The 16 units would be valued at $11 per one while the remaining 2 units would be valued at price of the purchase made on August 3 which cost $10 each
costs of goods sold=($11*16)+($10*2)
=$176+$20=$196
The costs of goods sold would be $196 if FIFO method of inventory valuation is used
Answer:
Translational equivalence
Explanation:
Translational equivalence -
It refers to the resemblance in the word in a particular language with its translation in other language , is referred to as translational equivalence .
The similarity can lead to any confusion or problem and hence , from the question ,
Claudia hires a translator of both the languages i.e. , english and spain , in order to avoid the problem of Translational equivalence .
Hence , the correct answer is Translational equivalence .
Answer:
The electrical action has the better expected monetary value with 492,000
Explanation:
We will multiply the expected outcome by their probability then, we add them to get the expected monetary value per option:
![\left[\begin{array}{ccccc}$WIND-UP&$Return&$Probability&$Weight\\$Light&325000&0.1&32500\\$Morerate&190000&0.3&57000\\$Heavy&170000&0.6&102000\\$Total&&1&191500\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D%24WIND-UP%26%24Return%26%24Probability%26%24Weight%5C%5C%24Light%26325000%260.1%2632500%5C%5C%24Morerate%26190000%260.3%2657000%5C%5C%24Heavy%26170000%260.6%26102000%5C%5C%24Total%26%261%26191500%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cccc}$PNEUMATIC&Return&Probability&Weight\\$Light&300000&0.1&30000\\$Morerate&420000&0.3&126000\\$Heavy&400000&0.6&240000\\$Total&&1&396000\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%24PNEUMATIC%26Return%26Probability%26Weight%5C%5C%24Light%26300000%260.1%2630000%5C%5C%24Morerate%26420000%260.3%26126000%5C%5C%24Heavy%26400000%260.6%26240000%5C%5C%24Total%26%261%26396000%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cccc}$Electrical&Return&Probability&Weight\\$Light&-600000&0.1&-60000\\$Morerate&240000&0.3&72000\\$Heavy&800000&0.6&480000\\$Total&&1&492000\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%24Electrical%26Return%26Probability%26Weight%5C%5C%24Light%26-600000%260.1%26-60000%5C%5C%24Morerate%26240000%260.3%2672000%5C%5C%24Heavy%26800000%260.6%26480000%5C%5C%24Total%26%261%26492000%5C%5C%5Cend%7Barray%7D%5Cright%5D)
True because they take notes on the security and the routines.
Answer:
Results are below.
Explanation:
Giving the following information:
Purchase price= $66,000
Salvage value= $5,700
Useful life= 6
F<u>irst, we need to calculate the annual depreciation using the following formula:</u>
<u></u>
Annual depreciation= (original cost - salvage value)/estimated life (years)
Annual depreciation= (66,000 - 5,700) / 6= 10,050
<u>2017:</u>
Annual depreciation= (10,050/12)*3= $2,512.5
<u>2018:</u>
Annual depreciation= $10,050
