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3 years ago

13

What’s the answer to this math problem

2 answers:

LuckyWell [14K]3 years ago

8 0

Y/x^2

You have to subtract or add exponents

Alona [7]3 years ago

3 0

If its same with the one I know then the ans would be..
y y^2 over x^1 x

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aleksley [76]

Answer:

The equivalent expressions are:

$b1=\frac{2a}{h}-b2$

$h=\frac{2a}{b1+b2}$

Step-by-step explanation:

Given equation for finding area of a trapezoid:

$a=\frac{1}{2}(b1+b2)h\\$

where $a$ represents area, $h$ represents height and $b1\ and\ b2$ represents the base lengths of the trapezoid.

Evaluating $h$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $b1+b2$

$\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}$

$\frac{2a}{b1+b2}=h$

$\therefore h=\frac{2a}{b1+b2}$

Evaluating $b1$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $h$

$\frac{2a}{h}=\frac{(b1+b2)h}{h}$

$\frac{2a}{h}=b1+b2$

Subtracting both sides by $b2$

$\frac{2a}{h}-b2=b1+b2-b2$

$\frac{2a}{h}-b2=b1$

$\therefore b1=\frac{2a}{h}-b2$

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