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3 years ago

Labels on chemical containers do not include all the same information as found on the SDS true or false

Physics

2 answers:

Firlakuza [10]3 years ago

4 0

Answer:

This is true that there are not same information on the lable and the same chemical containrs.

Further Explanation:

A similar item identifier must be both on the label and in section 1 of the SDS. ... Here might be one sign word on the label no matter how many dangers a chemical may have.

Further Explanation:

Explanation:

These are the numerical of physics and can be solved very easily we can easily calculate the answer if we know the rules of mathematics.

What Is a Safety Data Sheet (SDS)?

Chemical manufacturers, distributors, or shippers are required by the Occupational Safety and Health Administration (OSHA) to give a SDS for any conceivably hazardous chemical substance. SDSs are a piece of the Globally Harmonized System for Hazard Communication (GHS).

Hope you will understand all of my discussion and can understand my discussion and you know all about the topic.

Answer Details:

Subject: Physics .

Level: High school .

keywords:

Further Explanation:

Explanation:

What Is a Safety Data Sheet (SDS)?

For further Evaluation:

brainly.com/question/6362387

brainly.com/question/12938965

raketka [301]3 years ago

3 0

the answer is: True.

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Find the slope of the line containing the two points (1,-1) and 7-5,-3). (1 point)

katrin [286]

Answer:

$m = \frac{-2}{3}$

Explanation:

Given

Points: (1,-1) and (-5,3)

Required

Determine the slope

The slope of a line is represented by m and is calculated as thus;

$m = \frac{y_1 - y_2}{x_1 - x_2}$

Where

$(x_1,y_1) = (1,-1)$

$(x_2,y_2) = (-5,3)$

Substitute these values in the given formula

$m = \frac{-1 - 3}{1 - (-5)}$

$m = \frac{-1 - 3}{1 +5}$

$m = \frac{-4}{6}$

Simplify fraction

$m = \frac{-2}{3}$

Hence, the slope of the line is $m = \frac{-2}{3}$

5 0

3 years ago

Using a rope that will snap if the tension in it exceeds 387 N, you need to lower a bundle of old roofing material weighing 449

Anni [7]

Answer:

(a) $a\approx1.4 m.s^{-2}$

(b) $v\approx 4.133 m.s^{-1}$

Explanation:

Given:

Limiting tension of snapping of the rope, T= 387 N

Weight of the object to be lifted, $w=449 N$

∴mass, $\Rightarrow m= 45.8163 kg$

height of letting down the weight, h = 6.1 m

(a)

Now,

The force to be compensated for being on the verge of snapping:

(T-w) = 62 N

Therefore, we need to produce and acceleration equivalent to the above force.

∵ $F=m.a$

$62=45.8163\times a$

$a= \frac{62}{45.8163}$

$a\approx 1.4 m.s^{-2}$

(b)

From the equation of motion ,we have:

$v^{2} =u^{2} +2a.s$ ....................(2)

where:

u= initial velocity= 0 (here, starting from rest)

v= final velocity = ?

$a= 1.4 m.s^{-2}$

s= displacement =h =6.1 m

Now, putting the values in eq. (2)

$v^2= 0^2 + 2\times 1.4\times 6.1$

$v\approx 4.133 m.s^{-1}$ is the velocity with which the body will hit the ground in the given conditions.

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4 years ago

A 0.10 kg meter stick is held perpendicular to a vertical wall by a 2.5 mm string going from the wall to the far end of the stic

il63 [147K]

Explanation:

Sum of moments = 0 (Equilibrium)

T . cos (Q)*L = m*g*L/2

$cos Q = \frac{\sqrt{(2.5^2 - L^2) } }{2.5}$

$T*\frac{\sqrt{(2.5^2 - L^2) } }{2.5} * L = 0.1 *9.81*L/2$

$T = \frac{2.4525}{\sqrt{(2.5)^2 - L^2} }$

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$T = \frac{1.962}{\sqrt{(2)^2 - L^2} }$

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3 years ago

Cathode-ray tubes produce images on the principle of induced emf. true or false?

yan [13]

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3 years ago

Please fill in question 3 (i) fast please science homework

Kitty [74]

The answers are 3.3kWh, 1.2kWh, and 120kWh.

Multiply the amount of kW used per hour by the amount of time it was powered and you receive your answer.

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3 years ago