g A certain elevator cab has a total run of 195 m and a maximum speed is 306 m/min, and it accelerates from rest and then back t
o rest at 1.19 m/s2. (a) How far does the cab move while accelerating to full speed from rest
1 answer:
Answer:
About 23 meters
Explanation:
To do this, you'll want to apply one of the kinematic equations to find the time it takes for the cabin to reach max velocity from rest. (Use the max velocity as V_f and V_i=0)
Then, you can find the distance travelled during the acceleration by equating the acceleration to the change in distance of the time squared.
My work is in the attachment, comment if you have any questions.
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Answer:
Explanation:
Let the required velocity of rocket be v .
We shall use the formula of time dilation to find the velocity of rocket .
t =
t = 430
t' = 38
= .0078
=.9922
= .996
v = .996 x 3 x 10⁸ m /s
= 2.988 x 10⁸ m /s
B )
Kinetic energy of rocket
= 1/2 m v²
= .5 x 20000 x (2.988 x 10⁸ )²
= 8.9 x 10²⁰ J .
C )
This energy is 8.9 times the energy requirement of United states in the year 2005 .