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Jet001 [13]
4 years ago
15

A shunt resistance of 8 Ω is connected to a galvanometer of resistance of 100 Ω. The current in the galvanometer is 0.42 A. What

is the current in the circuit?
Physics
1 answer:
GuDViN [60]4 years ago
3 0
I have no idea sorry hm 111111
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7. An engineer is using a wire that has a resistance of 1.5 . This resistance is too high for the application he is designing. T
Veronika [31]

Answer and Explanation:

We know that resistance R=\frac{\rho l}{A}  from the given equation of resistance it is clear that resistance depends on resistivity length  and area of the material but we can not change the length because it is given that the length must be 2.5 cm long.

So we can do two two things to reduce the resistance

  1. increase the cross sectional area
  2. decrease the resistivity of the material
7 0
3 years ago
Science 8 - Electromagnetic Spectrum Worksheet
yuradex [85]

Answer:

1. Electromagnetic spectrum

2. Electromagnetic radiation

3. Radiant energy

4. Infared  waves

5. Electricmagnetic radiation or Infared waves

6. Radio waves

7. Gamma rays

8. Radio waves

9. Ultraviolet rays

10. This is because it doesn’t contain water or a substance.

11. You should use sunscree and a hat to protect your skin from UV light that might  cause skin cancer.

Hope this helps

7 0
3 years ago
What happens to the resistance of a wire as it gets wet
frozen [14]

It will cause corrosion of the wire inside

8 0
3 years ago
You design toys for a toy company. Your boss wants you to hook up the lights in the toy car you are working on in the cheapest w
bezimeni [28]

Answer:

put the car on fire

Explanation:

if you put it on fire you would have a lot of light now

7 0
3 years ago
Read 2 more answers
Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.
kompoz [17]

Answer:

1.312 x 10⁻¹² J/nucleon

Explanation:

mass of ¹³⁶Ba = 135.905 amu

¹³⁶Ba contain 56 proton and 80 neutron

mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x  1.00728 amu + 80 x 1.00867 amu

                      = 137.10128 amu

mass defect = 137.10128 - 135.905

                    = 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

                     = 1.9858 x 10⁻²⁷ Kg

speed of light = 3 x 10⁸ m/s

binding energy,

E = mass defect x c²

E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²

E = 17.87 x 10⁻¹¹ J/atom

now,

binding energy per nucleon =\dfrac{17.87\times 10^{-11}}{136}

                                              = 0.1312 x 10⁻¹¹ J/nucleon

                                              = 1.312 x 10⁻¹² J/nucleon

4 0
3 years ago
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