3 years ago

What value of x makes the equation true? x+41=-90 i need help

Mathematics

1 answer:

zhuklara [117]3 years ago

6 0

Answer:

Step-by-step explanation:

x+41=-90 (original problem)

-41 -41 (you must get rid of the common factors by doing the opposite on both sides)

x= -132 (add -90 and -41 to get -132)

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Constructive proof: There exists an integer x such that: (x^3)/5 > x^2

Lana71 [14]

Answer:

$x>5$

Step-by-step explanation:

We are asked to find an integer x such that $\frac{x^3}{5}>x^2$ .

First of all, we will multiply both sides of inequality by 5.

$\frac{x^3}{5}>x^2$

$\frac{x^3}{5}*5>5*x^2$

$x^3>5x^2$

Divide both sides by $x^2$ :

$\frac{x^3}{x^2}>\frac{5x^2}{x^2}$

$x>5$

Therefore, the value of x is any number greater than 5.

3 0

3 years ago

If sin (7y) = cos (5y + 14), find y.

Reil [10]

Answer:

Step-by-step explanation:

sin(7y)=cos(5y+14)=sin(90-(5y+14))=sin(76-5y)

7y=76-5y

12y=76

y=76/12=19/3

sin(7y)=cos (5y+14)=sin (90+(5y+14))=sin (5y+104)

7y=5y+104

2y=104

y=52

7 0

4 years ago

Can someone help me with this one plz

natali 33 [55]

I think this is how you do it...hope it helps

3 0

3 years ago

Read 2 more answers

Find the slope of the line that is perpendicular to the joining line P (2,-3) and Q (-3,-2)

azamat

m =(y2-y1)/(x2-x1)

m =(-2 + 3 )/(-3 -2)

m = 1/-5

m = -1/5

slope of the line that is perpendicular = 5

8 0

3 years ago

Can you help me figure this out please

Anna007 [38]

Answer:

C & D

Step-by-step explanation:

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3 years ago