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You have to change the denominator the the least common multiple then multiply the numerator by the number you multiplied it’s denominator with.
Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
60 minutes is an hour , you haven't given out what the 15, 30 and 60 are , and the 1 , 2 and 4 are(minutes or hours?)
The product of two integers is an integer; the difference of two integers is an integer; a rational is defined as one integer divided by another non-zero integer.<span>
the diference of two numbers is always rational</span>
Well...their relations but not functions
