Answer:
8.44 atm
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2.25 L
Initial temperature (T₁) = 350 K
Initial pressure (P₁) = 1.75 atm
Final volume (V₂) = 1 L
Final temperature (T₂) = 750 K
Final pressure (P₂) =?
The final pressure of the gas can be obtained as illustrated below:
P₁V₁/T₁ = P₂V₂/T₂
1.75 × 2.25 / 350 = P₂ × 1 / 750
3.9375 / 350 = P₂ / 750
Cross multiply
350 × P₂ = 3.9375 × 750
350 × P₂ = 2953.125
Divide both side by 350
P₂ = 2953.125 / 350
P₂ = 8.44 atm
Thus, the final pressure of the gas is 8.44 atm.
Answer:
I just did the assignment it's "decreases"
Explanation:
If you guys came from Ed-genuity (i'm writing it like that because apperantly that is a swear word?) That means the next questions are "As you move from left to right across the periodic table, electronegativity..." and "As you move from top to bottom within a group, the first ionization energy...".
for electronegativity, it's increases and for ionization energy it's decreases. Hope this helps!
In HCl-HCl, the hydrogen-chlorine link is a polar covalent bond. It is produced when two atoms share an electron pair.
When atoms with various electronegativities share electrons in a covalent link, the result is a polar covalent bond. Think about the molecule of hydrogen chloride (HCl). In order to generate an inert gas electron configuration, each atom of HCl needs an additional electron. Despite having a stronger electronegativity than hydrogen, the chlorine atom cannot remove an electron from hydrogen due to its inability to attract electrons. As a result, a polar covalent bond in hydrogen chloride has an unbalanced distribution of bonding electrons.
Learn more about electronegativity here-
brainly.com/question/17762711
#SPJ4
Answer:
Glow sticks and match would be light emission, slime would be preciptate, and cookies would be gas.
Explanation:
Since monosaccharides are the simplest units of carbohydrates, then they are made up of carbon, hydrogen, and oxygen atoms.
empirical formula : CxH2xOx
where
Monosaccharides can be classified by the number x of carbon atoms they contain: triose(3) tetrose (4), pentose (5), hexose (6), heptose (7), and so on.
