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ale4655 [162]
3 years ago
8

What two elements comprise most of a nebula? question 5 options: hydrogen and helium hydrogen and nitrogen oxygen and hydrogen c

arbon and hydrogen helium and lithium?
Chemistry
2 answers:
OleMash [197]3 years ago
5 0
hydrogen and helium and the most abundant elements in a nebula.
nlexa [21]3 years ago
3 0

Hydrogen and helium took the test was correct!

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If 15.6g of titanium reacts with oxygen to form 20g of titanium oxide what is the mass of oxegen
Nata [24]
15.6+m=20
M=20-15.6
M=4.4g
4 0
3 years ago
Which of the following is the correct set up AND answer to convert 6.25 x
BlackZzzverrR [31]

Answer:

Explanation:

How many mols do you have?

1 mol = 6.02 * 10^23 atoms

x mol = 6.25 * 10 ^32 atoms

1/x = 6.02*10^23 / 6.25 * 10^32        Cross multiply

6.02 * 10^23 * x = 1 * 6.25 * 10^32    Divide by 6.02 * 10^23

x = 6.25 * 10*32/ 6.02 ^10^23

x = 1.038 * 10^9 mols which is quite large.

Find the number of grams. (Use the value for copper on your periodic table. I will just use an approximate number.)\

1 mol of copper = 63 grams.

1.038 * 10^9 mols of copper = x

1/1.038 * 10^9 = 63/x         Cross multiply

x = 1.038 * 10^9 * 63

x = 6.54 * 10^10 grams of copper.

7 0
3 years ago
Which of the following is closest to the meaning of the term ancestor?
rjkz [21]

Answer:

I would say A

Explanation:

our ancestors are the people that lived long before us

8 0
3 years ago
Read 2 more answers
Which group on the Periodic Table reacts violently with water by igniting hydrogen gas?
Artemon [7]

Answer:

the answer would be Halogens

4 0
3 years ago
28 mL of 0.10 M HCl is added to 60.0 mL of 0.10 M Sr(OH)2. Determine the concentration of OHin the resulting solution.
serg [7]

Answer:

Explanation:

Sr(OH)₂.+ 2HCl = SrCl₂ + 2H₂O

Moles of HCl in 28mL of .10 M HCl = .028 x .1 = .0028 moles .

Moles of Sr(OH)₂ in 60mL of .10 M Sr(OH)₂ = .060 x .1 = .0060 moles

2 moles of HCl  reacts with 1 mole of Sr(OH)₂

.0028 moles of HCl  reacts with .0014  mole of Sr(OH)₂

moles of Sr(OH)₂ remaining = .0060 - .0014 = .0046 moles .

Sr(OH)₂  = Sr⁺  +  2OH⁻

1 mole                  2 mole

.0046                    .0092

Total volume of solution = 88 mL .

88 mL of solution contains .0092 moles of OH⁻

concentration of OH⁻ = .0092 / .088

= .1045 M  .

6 0
2 years ago
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