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romanna [79]
3 years ago
13

What is 9 ×7 plus 1500

Mathematics
2 answers:
dolphi86 [110]3 years ago
3 0
Just times 9 x 7 = 63 so, just add it to 1500, which leaves you with your answer. Which is.... 1563 

Hope that helped u!!!!!

Mars2501 [29]3 years ago
3 0
9x7= 63
63+1500=1563
therefore the answer is 1563

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In a right triangle, a and b are the lengths of the legs and c is the length of the hypotenuse.
lorasvet [3.4K]

Answer:

P=23.4

Step-by-step explanation:

so using the pytogoren theroum

c2-b2= a2

so a= 6.9

so P= 6.9+6.8+9.7=23.4

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7 0
3 years ago
2. Which equation does not represent the identity property of multiplication? 55/55x 3= 17 x 1= 9/1 x 4 11/11 x4
melisa1 [442]

Answer:

Step-by-step explanation:

\dfrac{9}{1}*4=9*4 which does not represent the identity property of multiplication.

Rest all represents the identity property of multiplication.

\dfrac{55}{55}*3 = 1*3 = 3\\\\\\17*1=17\\\\\\\dfrac{11}{11}*4=1*4=4

5 0
2 years ago
What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers
Dafna1 [17]

Answer:

a) \pm 8\frac{x^{5}}{5}+C

b) \pm 4 sin(2x) + C

Step-by-step explanation:

Given integrals are:

a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx ---(1)

b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx---- (2)

Standard form

                L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx

<h3>Part A</h3>

compare (1) with standard form

[f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C

<h3>Part B</h3>

Compare (2) with standard form

[f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C

5 0
3 years ago
Please help out and if you can leave a formula
PSYCHO15rus [73]
Apples . . . . . 40 pounds

Oranges . . . .  5 pounds

Ratio of apples to oranges  =  40 pounds / 5 pounds  =  8 / 1 .
5 0
3 years ago
Help me out im stuck on these 2 problems
solniwko [45]
1. A=PiR^2
A=3.14 x 6^6
A=3.14 x 36
A=113.04 m^2

V= AxH
V= 113.04 x 10
V= 1130.4 m^3
4 0
3 years ago
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